是否有一种方法可以在Java方法中传递回调函数?

我试图模拟的行为是一个。net委托被传递给一个函数。

我看到有人建议创建一个单独的对象,但这似乎有点过分,但我意识到有时过度是做事的唯一方法。


当前回答

当我在Java中需要这种功能时,我通常使用观察者模式。它确实意味着一个额外的对象,但我认为这是一种干净的方式,而且是一种被广泛理解的模式,有助于提高代码的可读性。

其他回答

我尝试使用java.lang.reflect来实现'callback',这是一个示例:

package StackOverflowQ443708_JavaCallBackTest;

import java.lang.reflect.*;
import java.util.concurrent.*;

class MyTimer
{
    ExecutorService EXE =
        //Executors.newCachedThreadPool ();
        Executors.newSingleThreadExecutor ();

    public static void PrintLine ()
    {
        System.out.println ("--------------------------------------------------------------------------------");
    }

    public void SetTimer (final int timeout, final Object obj, final String methodName, final Object... args)
    {
        SetTimer (timeout, obj, false, methodName, args);
    }
    public void SetTimer (final int timeout, final Object obj, final boolean isStatic, final String methodName, final Object... args)
    {
        Class<?>[] argTypes = null;
        if (args != null)
        {
            argTypes = new Class<?> [args.length];
            for (int i=0; i<args.length; i++)
            {
                argTypes[i] = args[i].getClass ();
            }
        }

        SetTimer (timeout, obj, isStatic, methodName, argTypes, args);
    }
    public void SetTimer (final int timeout, final Object obj, final String methodName, final Class<?>[] argTypes, final Object... args)
    {
        SetTimer (timeout, obj, false, methodName, argTypes, args);
    }
    public void SetTimer (final int timeout, final Object obj, final boolean isStatic, final String methodName, final Class<?>[] argTypes, final Object... args)
    {
        EXE.execute (
            new Runnable()
            {
                public void run ()
                {
                    Class<?> c;
                    Method method;
                    try
                    {
                        if (isStatic) c = (Class<?>)obj;
                        else c = obj.getClass ();

                        System.out.println ("Wait for " + timeout + " seconds to invoke " + c.getSimpleName () + "::[" + methodName + "]");
                        TimeUnit.SECONDS.sleep (timeout);
                        System.out.println ();
                        System.out.println ("invoking " + c.getSimpleName () + "::[" + methodName + "]...");
                        PrintLine ();
                        method = c.getDeclaredMethod (methodName, argTypes);
                        method.invoke (obj, args);
                    }
                    catch (Exception e)
                    {
                        e.printStackTrace();
                    }
                    finally
                    {
                        PrintLine ();
                    }
                }
            }
        );
    }
    public void ShutdownTimer ()
    {
        EXE.shutdown ();
    }
}

public class CallBackTest
{
    public void onUserTimeout ()
    {
        System.out.println ("onUserTimeout");
    }
    public void onTestEnd ()
    {
        System.out.println ("onTestEnd");
    }
    public void NullParameterTest (String sParam, int iParam)
    {
        System.out.println ("NullParameterTest: String parameter=" + sParam + ", int parameter=" + iParam);
    }
    public static void main (String[] args)
    {
        CallBackTest test = new CallBackTest ();
        MyTimer timer = new MyTimer ();

        timer.SetTimer ((int)(Math.random ()*10), test, "onUserTimeout");
        timer.SetTimer ((int)(Math.random ()*10), test, "onTestEnd");
        timer.SetTimer ((int)(Math.random ()*10), test, "A-Method-Which-Is-Not-Exists");    // java.lang.NoSuchMethodException

        timer.SetTimer ((int)(Math.random ()*10), System.out, "println", "this is an argument of System.out.println() which is called by timer");
        timer.SetTimer ((int)(Math.random ()*10), System.class, true, "currentTimeMillis");
        timer.SetTimer ((int)(Math.random ()*10), System.class, true, "currentTimeMillis", "Should-Not-Pass-Arguments");    // java.lang.NoSuchMethodException

        timer.SetTimer ((int)(Math.random ()*10), String.class, true, "format", "%d %X", 100, 200); // java.lang.NoSuchMethodException
        timer.SetTimer ((int)(Math.random ()*10), String.class, true, "format", "%d %X", new Object[]{100, 200});

        timer.SetTimer ((int)(Math.random ()*10), test, "NullParameterTest", new Class<?>[]{String.class, int.class}, null, 888);

        timer.ShutdownTimer ();
    }
}

我发现使用反射库实现的想法很有趣,并提出了这个,我认为它工作得很好。唯一的缺点是丢失了传递有效参数的编译时检查。

public class CallBack {
    private String methodName;
    private Object scope;

    public CallBack(Object scope, String methodName) {
        this.methodName = methodName;
        this.scope = scope;
    }

    public Object invoke(Object... parameters) throws InvocationTargetException, IllegalAccessException, NoSuchMethodException {
        Method method = scope.getClass().getMethod(methodName, getParameterClasses(parameters));
        return method.invoke(scope, parameters);
    }

    private Class[] getParameterClasses(Object... parameters) {
        Class[] classes = new Class[parameters.length];
        for (int i=0; i < classes.length; i++) {
            classes[i] = parameters[i].getClass();
        }
        return classes;
    }
}

你可以这样使用它

public class CallBackTest {
    @Test
    public void testCallBack() throws NoSuchMethodException, InvocationTargetException, IllegalAccessException {
        TestClass testClass = new TestClass();
        CallBack callBack = new CallBack(testClass, "hello");
        callBack.invoke();
        callBack.invoke("Fred");
    }

    public class TestClass {
        public void hello() {
            System.out.println("Hello World");
        }

        public void hello(String name) {
            System.out.println("Hello " + name);
        }
    }
}

它有点旧了,但不管怎样……我发现Peter Wilkinson的答案很好,除了它不适用于像int/Integer这样的原始类型。 问题是参数[i]的. getclass(),它返回实例java.lang。整数,另一方面,getMethod(methodName,parameters[])不会正确解释(Java的错误)…

我结合了丹尼尔·斯皮沃克(Daniel Spiewak)的建议(在他的回答中);成功的步骤包括:捕捉NoSuchMethodException -> getMethods() ->通过method.getName() ->查找匹配的一个,然后显式遍历参数列表并应用Daniels解决方案,例如识别类型匹配和签名匹配。

从Java 8开始,有lambda和方法引用:

Oracle文档:Lambda表达式 Oracle文档:方法引用

例如,如果你想要一个功能接口a -> B,你可以使用:

import java.util.function.Function;

public MyClass {
    public static String applyFunction(String name, Function<String,String> function){
        return function.apply(name);
    }
}

你可以这样称呼它:

MyClass.applyFunction("42", str -> "the answer is: " + str);
// returns "the answer is: 42"

你也可以通过类方法。例如:

@Value // lombok
public class PrefixAppender {
    private String prefix;

    public String addPrefix(String suffix){
        return prefix +":"+suffix;
    }
}

然后你可以这样做:

PrefixAppender prefixAppender= new PrefixAppender("prefix");
MyClass.applyFunction("some text", prefixAppender::addPrefix);
// returns "prefix:some text"

注意:

这里我使用了函数接口Function<A,B>,但是包java.util.function中还有许多其他的接口。最值得注意的是

供应商:void -> 消费者:A ->无效 双消费者:(A,B) ->无效 功能:A -> B biffunction:(A,B) -> C

以及许多其他专门研究某些输入/输出类型的程序。然后,如果它不提供你需要的,你可以创建自己的FunctionalInterface:

@FunctionalInterface
interface Function3<In1, In2, In3, Out> { // (In1,In2,In3) -> Out
    public Out apply(In1 in1, In2 in2, In3 in3);
}

使用示例:

String computeAnswer(Function3<String, Integer, Integer, String> f){
    return f.apply("6x9=", 6, 9);
}

computeAnswer((question, a, b) -> question + "42");
// "6*9=42"

你也可以用抛出异常来实现:

@FunctionalInterface
interface FallibleFunction<In, Out, Ex extends Exception> {
    Out get(In input) throws Ex;
}
public <Ex extends IOException> String yo(FallibleFunction<Integer, String, Ex> f) throws Ex {
    return f.get(42);
}

这在Java 8中使用lambdas非常容易。

public interface Callback {
    void callback();
}

public class Main {
    public static void main(String[] args) {
        methodThatExpectsACallback(() -> System.out.println("I am the callback."));
    }
    private static void methodThatExpectsACallback(Callback callback){
        System.out.println("I am the method.");
        callback.callback();
    }
}