下面是我编写的一个缓慢向下滚动到targets元素的方法

你可以将CSS选择器中元素的y号位置传递给它

它就像我们通过鼠标滚轮一样滚动

一旦这个方法被调用，你用相同的驱动对象再次调用它，但是使用新的目标元素，它将在元素存在的任何地方向上/向下滚动

def slow_scroll_to_element(self, driver, element_selector=None, target_yth_location=None):
    current_scroll_position = int(driver.execute_script("return window.scrollY"))
    
    if element_selector:
        target_yth_location = int(driver.execute_script("return document.querySelector('{}').getBoundingClientRect()['top'] + window.scrollY".format(element_selector)))
    
    scrollSpeed = 100 if target_yth_location-current_scroll_position > 0 else -100

    def chunks(a, n):
        k, m = divmod(len(a), n)
        return (a[i*k+min(i, m):(i+1)*k+min(i+1, m)] for i in range(n))
    
    for l in list(chunks(list(range(current_scroll_position, target_yth_location, scrollSpeed)) + list([target_yth_location+(-scrollSpeed if scrollSpeed > 0 else scrollSpeed)]), 3)):
        for pos in l:
            driver.execute_script("window.scrollTo(0, "+str(pos)+");")
            time.sleep(0.1)
        time.sleep(random.randint(1,3))

出于我的目的，我想要更多地向下滚动，记住窗口的位置。我的解决方案类似，使用window.scrollY

driver.execute_script("window.scrollTo(0, window.scrollY + 200)")

哪个会到当前的y轴滚动位置+ 200

医生说 类ActionChains完成工作:

from selenium import webdriver
from selenium.webdriver import ActionChains

driver = webdriver.Firefox()
action_chains = ActionChains(driver)
action_chains.scroll(x: int, y: int, delta_x: int, delta_y: int, duration: int = 0, origin: str = 'viewport').perform()

element=find_element_by_xpath("xpath of the li you are trying to access")

element.location_once_scrolled_into_view

当我试图进入一个不可见的“li”时，这很有帮助。

这是你如何向下滚动网页:

driver.execute_script("window.scrollTo(0, 1000);")

这段代码滚动到底部，但不需要每次都等待。它会不断滚动，然后在底部停止(或超时)

from selenium import webdriver
import time

driver = webdriver.Chrome(executable_path='chromedriver.exe')
driver.get('https://example.com')

pre_scroll_height = driver.execute_script('return document.body.scrollHeight;')
run_time, max_run_time = 0, 1
while True:
    iteration_start = time.time()
    # Scroll webpage, the 100 allows for a more 'aggressive' scroll
    driver.execute_script('window.scrollTo(0, 100*document.body.scrollHeight);')

    post_scroll_height = driver.execute_script('return document.body.scrollHeight;')

    scrolled = post_scroll_height != pre_scroll_height
    timed_out = run_time >= max_run_time

    if scrolled:
        run_time = 0
        pre_scroll_height = post_scroll_height
    elif not scrolled and not timed_out:
        run_time += time.time() - iteration_start
    elif not scrolled and timed_out:
        break

# closing the driver is optional 
driver.close()

这比每次等待0.5-3秒的响应要快得多，因为每次响应可能需要0.1秒