好吧，我几乎什么都试过了，但我不能让它工作。
我有一个带有ImageField的Django模型
我有通过HTTP下载图像的代码(测试和工作)
图像直接保存到'upload_to'文件夹中(upload_to是在ImageField中设置的)
我所需要做的就是将已经存在的图像文件路径与ImageField关联起来
我用六种不同的方式写了这段代码。
The problem I'm running into is all of the code that I'm writing results in the following behavior:
(1) Django will make a 2nd file, (2) rename the new file, adding an _ to the end of the file name, then (3) not transfer any of the data over leaving it basically an empty re-named file. What's left in the 'upload_to' path is 2 files, one that is the actual image, and one that is the name of the image,but is empty, and of course the ImageField path is set to the empty file that Django try to create.
如果你不清楚，我将尝试说明:
## Image generation code runs....
/Upload
generated_image.jpg 4kb
## Attempt to set the ImageField path...
/Upload
generated_image.jpg 4kb
generated_image_.jpg 0kb
ImageField.Path = /Upload/generated_image_.jpg
我怎样才能做到这一点而不让Django重新存储文件呢?我真正想要的是这样的东西……
model.ImageField.path = generated_image_path
.．.当然这是行不通的。
是的，我已经看了这里的其他问题，比如这个问题，以及django doc on File
更新
经过进一步的测试，它只有在Windows Server上的Apache下运行时才会执行此行为。当在XP的“runserver”下运行时，它不会执行此行为。
我被难住了。
下面是在XP上成功运行的代码…
f = open(thumb_path, 'r')
model.thumbnail = File(f)
model.save()
我有一些代码，从网络上获取图像，并将其存储在模型中。重要的部分是:
from django.core.files import File # you need this somewhere
import urllib
# The following actually resides in a method of my model
result = urllib.urlretrieve(image_url) # image_url is a URL to an image
# self.photo is the ImageField
self.photo.save(
os.path.basename(self.url),
File(open(result[0], 'rb'))
)
self.save()
这有点令人困惑，因为它是从我的模型中提取出来的，有点脱离上下文，但重要的部分是:
从web中提取的图像不存储在upload_to文件夹中，而是由urllib.urlretrieve()存储为tempfile，然后丢弃。
ImageField.save()方法接受一个文件名(os.path.basename位)和一个django.core.files.File对象。
如果您有问题或需要澄清，请告诉我。
编辑:为了清晰起见，下面是模型(减去任何必需的import语句):
class CachedImage(models.Model):
url = models.CharField(max_length=255, unique=True)
photo = models.ImageField(upload_to=photo_path, blank=True)
def cache(self):
"""Store image locally if we have a URL"""
if self.url and not self.photo:
result = urllib.urlretrieve(self.url)
self.photo.save(
os.path.basename(self.url),
File(open(result[0], 'rb'))
)
self.save()
我所做的是创建我自己的存储，只是不会将文件保存到磁盘:
from django.core.files.storage import FileSystemStorage
class CustomStorage(FileSystemStorage):
def _open(self, name, mode='rb'):
return File(open(self.path(name), mode))
def _save(self, name, content):
# here, you should implement how the file is to be saved
# like on other machines or something, and return the name of the file.
# In our case, we just return the name, and disable any kind of save
return name
def get_available_name(self, name):
return name
然后，在我的模型中，对于我的ImageField，我使用了新的自定义存储:
from custom_storage import CustomStorage
custom_store = CustomStorage()
class Image(models.Model):
thumb = models.ImageField(storage=custom_store, upload_to='/some/path')
class Pin(models.Model):
"""Pin Class"""
image_link = models.CharField(max_length=255, null=True, blank=True)
image = models.ImageField(upload_to='images/', blank=True)
title = models.CharField(max_length=255, null=True, blank=True)
source_name = models.CharField(max_length=255, null=True, blank=True)
source_link = models.CharField(max_length=255, null=True, blank=True)
description = models.TextField(null=True, blank=True)
tags = models.ForeignKey(Tag, blank=True, null=True)
def __unicode__(self):
"""Unicode class."""
return unicode(self.image_link)
def save(self, *args, **kwargs):
"""Store image locally if we have a URL"""
if self.image_link and not self.image:
result = urllib.urlretrieve(self.image_link)
self.image.save(os.path.basename(self.image_link), File(open(result[0], 'r')))
self.save()
super(Pin, self).save()
