我在用

Window w = getWindow();
w.setTitle("My title");

要更改我当前活动的标题,但似乎不工作。

有人能告诉我怎么改变吗?


当前回答

如果你正在使用onCreateOptionsMenu,你也可以在onCreateOptionsMenu中添加setTitle代码。

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.menu, menu);

    setTitle("Neue Aktivität");
    return true;
}

其他回答

如果你想在Java文件中设置标题,那么写在你的活动onCreate

setTitle("Your Title");

如果你想在Manifest里写

    <activity
        android:name=".MainActivity"
        android:label="Your Title" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

代码帮助我更改了标题。

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_name);
    ActivityName.this.setTitle("Your Activity Title");}

这对我很管用。

public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
    View v = inflater.inflate(R.layout.fragment, container, false);
    getActivity().setTitle("My Title");
//...
}

如果你想要它一次,让系统处理剩下的(不是动态的),那么在你的manifest文件中这样做:

<application
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >
        <activity
            android:name=".MainActivity"
            android:label="@string/app_name_full" > //This is my custom title name on activity. <- The question is about this one.
            <intent-filter android:label="@string/app_launcher_name" > //This is my custom Icon title name (launcher name that you see in android apps/homescreen)
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
    </application>
setTitle(getResources().getText(R.string.MyTitle));