如果mydict不为空,则访问任意元素,如下:

mydict[mydict.keys()[0]]

还有什么更好的办法吗?


当前回答

子类化字典是一种方法,但效率不高。这里如果你提供一个整数,它将返回d[list(d)[n]],否则按预期访问字典:

class mydict(dict):
    def __getitem__(self, value):
        if isinstance(value, int):
            return self.get(list(self)[value])
        else:
            return self.get(value)

d = mydict({'a': 'hello', 'b': 'this', 'c': 'is', 'd': 'a',
            'e': 'test', 'f': 'dictionary', 'g': 'testing'})

d[0]    # 'hello'
d[1]    # 'this'
d['c']  # 'is'

其他回答

另一种方法是在一行中做到这一点,同时保持字典的完整性:

arbitrary_value = mydict.setdefault(*mydict.popitem())

popitem() returns a tuple of (key, value) for the last item that was added into the dictionary and this pair is passed into setdefault as positional arguments. The setdefault tries to insert key into mydict with value value if it doesn't already exist, but does nothing if does exist; and then returns the value of that key to the caller. Because we already popped the (key, value) pair out of the dictionary, we insert it back into it via setdefault and then proceed to return value, which is what we want.

没有外部库,适用于Python 2.7和3.x:

>>> list(set({"a":1, "b": 2}.values()))[0]
1

对于任意键,省略.values()

>>> list(set({"a":1, "b": 2}))[0]
'a'

子类化字典是一种方法,但效率不高。这里如果你提供一个整数,它将返回d[list(d)[n]],否则按预期访问字典:

class mydict(dict):
    def __getitem__(self, value):
        if isinstance(value, int):
            return self.get(list(self)[value])
        else:
            return self.get(value)

d = mydict({'a': 'hello', 'b': 'this', 'c': 'is', 'd': 'a',
            'e': 'test', 'f': 'dictionary', 'g': 'testing'})

d[0]    # 'hello'
d[1]    # 'this'
d['c']  # 'is'

这个怎么样。这里还没有提到。

Py 2和Py 3

a = {"a":2,"b":3}
a[list(a)[0]] # the first element is here
>>> 2

对于Python 2和3:

import six

six.next(six.itervalues(d))