如何在React.js中执行debounce ?

我想撤消handleOnChange。

我尝试debounce(这。handleOnChange, 200)但它不起作用。

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    // make ajax call
  }
});

当前回答

这里已经有很多好的信息了,但为了简洁。这对我很有用……

import React, {Component} from 'react';
import _ from 'lodash';

class MyComponent extends Component{
      constructor(props){
        super(props);
        this.handleChange = _.debounce(this.handleChange.bind(this),700);
      }; 

其他回答

这里有一个工作的TypeScript示例,供那些使用TS并想要debounce async函数的人使用。

function debounce<T extends (...args: any[]) => any>(time: number, func: T): (...funcArgs: Parameters<T>) => Promise<ReturnType<T>> {
     let timeout: Timeout;

     return (...args: Parameters<T>): Promise<ReturnType<T>> => new Promise((resolve) => {
         clearTimeout(timeout);
         timeout = setTimeout(() => {
             resolve(func(...args));
         }, time)
     });
 }

使用ES6 CLASS和React 15.x。X & lodash.debounce 我在这里使用React的refs,因为事件在内部失去了这个绑定。

class UserInput extends React.Component { constructor(props) { super(props); this.state = { userInput: "" }; this.updateInput = _.debounce(this.updateInput, 500); } updateInput(userInput) { this.setState({ userInput }); //OrderActions.updateValue(userInput);//do some server stuff } render() { return ( <div> <p> User typed: { this.state.userInput } </p> <input ref = "userValue" onChange = {() => this.updateInput(this.refs.userValue.value) } type = "text" / > </div> ); } } ReactDOM.render( < UserInput / > , document.getElementById('root') ); <script src="https://cdn.jsdelivr.net/npm/lodash@4.17.5/lodash.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> <div id="root"></div>

与其在debounce()中包装handleOnChange,不如在debounce()中包装回调函数中的ajax调用,从而不破坏事件对象。就像这样:

handleOnChange: function (event) {
   debounce(
     $.ajax({})
  , 250);
}

避免使用event.persist()——你想让React回收合成事件。我认为无论你使用类还是钩子,最干净的方法是将回调函数分成两部分:

没有deboundation的回调 只使用您需要的事件片段调用已撤销的函数(这样合成的事件就可以循环使用)

handleMouseOver = throttle(target => {
  console.log(target);
}, 1000);

onMouseOver = e => {
  this.handleMouseOver(e.target);
};

<div onMouseOver={this.onMouseOver} />

功能

const handleMouseOver = useRef(throttle(target => {
  console.log(target);
}, 1000));

function onMouseOver(e) {
  handleMouseOver.current(e.target);
}

<div onMouseOver={this.onMouseOver} />

注意,如果你的handleMouseOver函数从组件中使用状态,你应该使用usemo而不是useRef,并将它们作为依赖项传递,否则你将使用过时的数据(当然不适用于类)。

I was searching for a solution to the same problem and came across this thread as well as some others but they had the same problem: if you are trying to do a handleOnChange function and you need the value from an event target, you will get cannot read property value of null or some such error. In my case, I also needed to preserve the context of this inside the debounced function since I'm executing a fluxible action. Here's my solution, it works well for my use case so I'm leaving it here in case anyone comes across this thread:

// at top of file:
var myAction = require('../actions/someAction');

// inside React.createClass({...});

handleOnChange: function (event) {
    var value = event.target.value;
    var doAction = _.curry(this.context.executeAction, 2);

    // only one parameter gets passed into the curried function,
    // so the function passed as the first parameter to _.curry()
    // will not be executed until the second parameter is passed
    // which happens in the next function that is wrapped in _.debounce()
    debouncedOnChange(doAction(myAction), value);
},

debouncedOnChange: _.debounce(function(action, value) {
    action(value);
}, 300)