所有的答案都有深刻的见解

另一种方法是platform.python_version_tuple()

python3 -c “import platform; print(platform.python_version_tuple())”

(‘3’, ‘6’, ‘8’)

可以这样写:

#!/usr/bin/env/python
import sys
if sys.version_info<(2,6,0):
  sys.stderr.write("You need python 2.6 or later to run this script\n")
  exit(1)

在你的脚本顶部。

请注意，根据脚本中的其他内容，比目标版本更老的python甚至可能无法加载脚本，因此不会报告此错误。作为一种变通方法，您可以在一个脚本中运行上述操作，该脚本导入了更现代的代码。

从stdlib中使用平台的python_version:

from platform import python_version
print(python_version())

# 3.9.2

这只返回2.7 3.6或3.9

import sys
current_version = ".".join(map(str, sys.version_info[0:2]))

这是你通常需要的…

所有的答案都有深刻的见解

另一种方法是platform.python_version_tuple()

python3 -c “import platform; print(platform.python_version_tuple())”

(‘3’, ‘6’, ‘8’)

只是为了好玩，下面是在CPython 1.0-3.7b2, Pypy, Jython和Micropython上的一种方法。在现代代码中，这更像是一种新奇的做法。我将其作为http://stromberg.dnsalias.org/~strombrg/pythons/的一部分编写，这是一个脚本，用于在多个版本的python上同时测试一段代码，因此您可以轻松地了解哪些python特性与哪些版本的python兼容:

via_platform = 0
check_sys = 0
via_sys_version_info = 0
via_sys_version = 0
test_sys = 0
try:
    import platform
except (ImportError, NameError):
    # We have no platform module - try to get the info via the sys module
    check_sys = 1

if not check_sys:
    if hasattr(platform, "python_version"):
        via_platform = 1
    else:
        check_sys = 1

if check_sys:
    try:
        import sys
        test_sys = 1
    except (ImportError, NameError):
        # just let via_sys_version_info and via_sys_version remain False - we have no sys module
        pass

if test_sys:
    if hasattr(sys, "version_info"):
        via_sys_version_info = 1
    elif hasattr(sys, "version"):
        via_sys_version = 1
    else:
        # just let via_sys remain False
        pass

if via_platform:
    # This gives pretty good info, but is not available in older interpreters.  Also, micropython has a
    # platform module that does not really contain anything.
    print(platform.python_version())
elif via_sys_version_info:
    # This is compatible with some older interpreters, but does not give quite as much info.
    print("%s.%s.%s" % sys.version_info[:3])
elif via_sys_version:
    import string
    # This is compatible with some older interpreters, but does not give quite as much info.
    verbose_version = sys.version
    version_list = string.split(verbose_version)
    print(version_list[0])
else:
    print("unknown")