试试这个:

在当前日期上增加5天。

from datetime import datetime, timedelta

current_date = datetime.now()
end_date = current_date + timedelta(days=5) # Adding 5 days.
end_date_formatted = end_date.strftime('%Y-%m-%d')
print(end_date_formatted)

从当前日期减去5天。

from datetime import datetime, timedelta

current_date = datetime.now()
end_date = current_date + timedelta(days=-5) # Subtracting 5 days.
end_date_formatted = end_date.strftime('%Y-%m-%d')
print(end_date_formatted)

首先导入timedelta和date。

from datetime import timedelta, date

date.today()将返回今天的日期时间，然后你可以给它添加一个timedelta:

end_date = date.today() + timedelta(days=10)

我刚看到一条旧帖子:

我查过了，但大部分答案都是一样的。我喜欢其中的两个答案，所以我想检查一下这两种方法的效率。

第一种方法:使用DateTime模块 第二种方法:利用熊猫的图书馆

所以我运行了大约10k次测试，熊猫库方法要慢得多。所以我建议使用内置的DateTime模块。

from datetime import date, timedelta
import pandas as pd
import timeit

def using_datetime():
    pre_date = date(2013, 10, 10)
    day_date = pre_date + timedelta(days=5)
    return day_date

def using_pd():
    start_date = "10/10/2022"
    pd_date = pd.to_datetime(start_date)
    end_date = pd_date + pd.DateOffset(days=5)
    return end_date
    

for func in [using_datetime, using_pd]:
    print(f"{func.__name__} Time Took: ",  timeit.timeit(stmt=func, number=10000))
    
# Output 
# using_datetime Time Took:  0.009390000021085143
# using_pd Time Took:  2.1051381999859586

这可能会有帮助:

from datetime import date, timedelta
date1 = date(2011, 10, 10)
date2 = date1 + timedelta(days=5)
print (date2)

一般来说，你现在已经有了一个答案，但也许我创建的类也会有帮助。对我来说，它解决了我在Pyhon项目中遇到的所有需求。

class GetDate:
    def __init__(self, date, format="%Y-%m-%d"):
        self.tz = pytz.timezone("Europe/Warsaw")

        if isinstance(date, str):
            date = datetime.strptime(date, format)

        self.date = date.astimezone(self.tz)

    def time_delta_days(self, days):
        return self.date + timedelta(days=days)

    def time_delta_hours(self, hours):
        return self.date + timedelta(hours=hours)

    def time_delta_seconds(self, seconds):
        return self.date + timedelta(seconds=seconds)

    def get_minimum_time(self):
        return datetime.combine(self.date, time.min).astimezone(self.tz)

    def get_maximum_time(self):
        return datetime.combine(self.date, time.max).astimezone(self.tz)

    def get_month_first_day(self):
        return datetime(self.date.year, self.date.month, 1).astimezone(self.tz)

    def current(self):
        return self.date

    def get_month_last_day(self):
        lastDay = calendar.monthrange(self.date.year, self.date.month)[1]
        date = datetime(self.date.year, self.date.month, lastDay)
        return datetime.combine(date, time.max).astimezone(self.tz)

如何使用

self.tz = pytz.timezone("Europe/Warsaw") - here you define Time Zone you want to use in project GetDate("2019-08-08").current() - this will convert your string date to time aware object with timezone you defined in pt 1. Default string format is format="%Y-%m-%d" but feel free to change it. (eg. GetDate("2019-08-08 08:45", format="%Y-%m-%d %H:%M").current()) GetDate("2019-08-08").get_month_first_day() returns given date (string or object) month first day GetDate("2019-08-08").get_month_last_day() returns given date month last day GetDate("2019-08-08").minimum_time() returns given date day start GetDate("2019-08-08").maximum_time() returns given date day end GetDate("2019-08-08").time_delta_days({number_of_days}) returns given date + add {number of days} (you can also call: GetDate(timezone.now()).time_delta_days(-1) for yesterday) GetDate("2019-08-08").time_delta_haours({number_of_hours}) similar to pt 7 but working on hours GetDate("2019-08-08").time_delta_seconds({number_of_seconds}) similar to pt 7 but working on seconds

有时我们需要使用从日期到日期的搜索。如果使用date__range，则需要给to_date加上1天，否则queryset将为空。

例子:

from datetime import timedelta  

from_date  = parse_date(request.POST['from_date'])

to_date    = parse_date(request.POST['to_date']) + timedelta(days=1)

attendance_list = models.DailyAttendance.objects.filter(attdate__range = [from_date, to_date])