我想将我的项目打包在一个可执行的JAR中进行分发。

如何使Maven项目将所有依赖JAR打包到输出JAR中?


当前回答

已经有数百万个答案了。我想补充一下,如果您不需要在应用程序中添加entryPoint,那么您不需要<mainClass>。例如,API可能不一定有主方法。

Maven插件配置

  <build>
    <finalName>log-enrichment</finalName>
    <plugins>
      <plugin>
        <artifactId>maven-assembly-plugin</artifactId>
        <configuration>
          <descriptorRefs>
            <descriptorRef>jar-with-dependencies</descriptorRef>
          </descriptorRefs>
        </configuration>
      </plugin>
    </plugins>
  </build>

建筑

mvn clean compile assembly:single

验证

ll target/
total 35100
drwxrwx--- 1 root vboxsf     4096 Sep 29 16:25 ./
drwxrwx--- 1 root vboxsf     4096 Sep 29 16:25 ../
drwxrwx--- 1 root vboxsf        0 Sep 29 16:08 archive-tmp/
drwxrwx--- 1 root vboxsf        0 Sep 29 16:25 classes/
drwxrwx--- 1 root vboxsf        0 Sep 29 16:25 generated-sources/
drwxrwx--- 1 root vboxsf        0 Sep 29 16:25 generated-test-sources/
-rwxrwx--- 1 root vboxsf 35929841 Sep 29 16:10 log-enrichment-jar-with-dependencies.jar*
drwxrwx--- 1 root vboxsf        0 Sep 29 16:08 maven-status/

其他回答

对于任何想要从über JAR文件中排除特定依赖项的人来说,这是一个适合我的解决方案:

<project...>
    <dependencies>
        <dependency>
            <groupId>org.apache.spark</groupId>
            <artifactId>spark-core_2.11</artifactId>
            <version>1.6.1</version>
            <scope>provided</scope> <!--  <=============  -->
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <artifactId>maven-assembly-plugin</artifactId>
                <configuration>
                    <descriptorRefs>
                        <descriptorRef>jar-with-dependencies</descriptorRef>
                    </descriptorRefs>
                    <archive>
                        <manifest>
                            <mainClass>...</mainClass>
                        </manifest>
                    </archive>
                </configuration>
                <executions>
                    <execution>
                        <id>make-assembly</id>
                        <phase>package</phase>
                        <goals>
                            <goal>single</goal>
                        </goals>
                    </execution>
                </executions>
            </plugin>
        </plugins>
    </build>
</project>

它不是mvn程序集插件的配置,而是依赖项的属性。

这是我找到的最好的方法:

<plugin>
  <groupId>org.apache.maven.plugins</groupId>
  <artifactId>maven-jar-plugin</artifactId>
  <version>2.4</version>
  <configuration>
    <archive>
      <manifest>
      <addClasspath>true</addClasspath>
      <mainClass>com.myDomain.etc.MainClassName</mainClass>
      <classpathPrefix>dependency-jars/</classpathPrefix>
      </manifest>
    </archive>
  </configuration>
</plugin>

<plugin>
  <groupId>org.apache.maven.plugins</groupId>
  <artifactId>maven-dependency-plugin</artifactId>
  <version>2.5.1</version>
  <executions>
    <execution>
      <id>copy-dependencies</id>
      <phase>package</phase>
      <goals>
        <goal>copy-dependencies</goal>
      </goals>
      <configuration>
        <outputDirectory>
          ${project.build.directory}/dependency-jars/
        </outputDirectory>
      </configuration>
    </execution>
  </executions>
</plugin>

使用此配置,所有依赖项都将位于依赖项jar中。我的应用程序没有Main类,只有上下文类,但我的一个依赖项确实有一个Main类(com.myDomain.ec.MainClassName),它启动JMX服务器,并接收start或stop参数。因此,我可以这样启动我的应用程序:

java -jar ./lib/TestApp-1.0-SNAPSHOT.jar start

它的工作原理如下:

<plugin>
    <artifactId>maven-dependency-plugin</artifactId>
    <executions>
        <execution>
            <id>unpack-dependencies</id>
            <phase>generate-resources</phase>
            <goals>
                <goal>unpack-dependencies</goal>
            </goals>
        </execution>
    </executions>
</plugin>

解包必须处于生成资源阶段,否则将不作为资源包含。

您可以使用maven shade插件构建如下的über JAR文件:

<plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-shade-plugin</artifactId>
    <executions>
        <execution>
            <phase>package</phase>
            <goals>
                <goal>shade</goal>
            </goals>
        </execution>
    </executions>
</plugin>

在我看来,Ken Liu是对的。Maven依赖插件允许您扩展所有依赖项,然后可以将其视为资源。这允许您将它们包含在主工件中。使用汇编插件会创建一个很难修改的辅助工件——在我的例子中,我想添加自定义清单条目。我的POM文件最终为:

<project>
  ...
  <build>
    <plugins>
      <plugin>
        <groupId>org.apache.maven.plugins</groupId>
        <artifactId>maven-dependency-plugin</artifactId>
        <executions>
          <execution>
            <id>unpack-dependencies</id>
            <phase>package</phase>
            <goals>
              <goal>unpack-dependencies</goal>
            </goals>
          </execution>
        </executions>
      </plugin>
    </plugins>
    ...
    <resources>
      <resource>
        <directory>${basedir}/target/dependency</directory>
        <targetPath>/</targetPath>
      </resource>
    </resources>
  </build>
  ...
</project>