我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
当前回答
只需使用本机javascript Intl
您只需使用选项设置其值的格式
常量编号=1233445.5678console.log(新的Intl.NumberFormat('en-US',{style:'currency',currency:'USD'}).format(数字));
mozilla文档链接
其他回答
javascript数字格式化程序(以前在Google Code)
短、快、灵活但独立。接受标准数字格式,如#、##0.00或带否定的-000.####。接受任何国家/地区格式,如###0,00,#,###.##,#‘###.##或任何类型的非编号符号。接受任意数字分组。#、##、#0.000或#、####0.##均有效。接受任何冗余/万无一失的格式。##、###、##。#或0#、#00####0#都正常。自动数字舍入。简单的界面,只需提供如下掩码和值:格式(“0.0000”,3.141592)。在掩码中包含前缀和后缀
(摘自自述)
我建议使用Google可视化API中的NumberFormat类。
你可以这样做:
var formatter = new google.visualization.NumberFormat({
prefix: '$',
pattern: '#,###,###.##'
});
formatter.formatValue(1000000); // $ 1,000,000
Patrick热门答案的CoffeeScript:
Number::formatMoney = (decimalPlaces, decimalChar, thousandsChar) ->
n = this
c = decimalPlaces
d = decimalChar
t = thousandsChar
c = (if isNaN(c = Math.abs(c)) then 2 else c)
d = (if d is undefined then "." else d)
t = (if t is undefined then "," else t)
s = (if n < 0 then "-" else "")
i = parseInt(n = Math.abs(+n or 0).toFixed(c)) + ""
j = (if (j = i.length) > 3 then j % 3 else 0)
s + (if j then i.substr(0, j) + t else "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (if c then d + Math.abs(n - i).toFixed(c).slice(2) else "")
乔纳森·M的代码对我来说太复杂了,所以我重写了它,在Firefox v30上获得了30%的速度提升,在Chrome v35上获得了60%的速度提升(http://jsperf.com/number-formating2):
Number.prototype.formatNumber = function(decPlaces, thouSeparator, decSeparator) {
decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces;
decSeparator = decSeparator == undefined ? "." : decSeparator;
thouSeparator = thouSeparator == undefined ? "," : thouSeparator;
var n = this.toFixed(decPlaces);
if (decPlaces) {
var i = n.substr(0, n.length - (decPlaces + 1));
var j = decSeparator + n.substr(-decPlaces);
} else {
i = n;
j = '';
}
function reverse(str) {
var sr = '';
for (var l = str.length - 1; l >= 0; l--) {
sr += str.charAt(l);
}
return sr;
}
if (parseInt(i)) {
i = reverse(reverse(i).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator));
}
return i + j;
};
用法:
var sum = 123456789.5698;
var formatted = '$' + sum.formatNumber(2, ',', '.'); // "$123,456,789.57"
已经有好的答案了。这里有一个简单的乐趣尝试:
function currencyFormat(no) {
var ar = (+no).toFixed(2).split('.');
return [
numberFormat(ar[0] | 0),
'.',
ar[1]
].join('');
}
function numberFormat(no) {
var str = no + '';
var ar = [];
var i = str.length -1;
while(i >= 0) {
ar.push((str[i-2] || '') + (str[i-1] || '') + (str[i] || ''));
i = i-3;
}
return ar.reverse().join(',');
}
然后运行一些示例:
console.log(
currencyFormat(1),
currencyFormat(1200),
currencyFormat(123),
currencyFormat(9870000),
currencyFormat(12345),
currencyFormat(123456.232)
)