如何在JavaScript中获得当前时间并在时间选择器中使用它?

我尝试了var x = Date(),得到:

2012年5月15日星期二05:45:40 GMT-0500

但我只需要现在的时间,比如05:45

我怎么把它赋值给变量呢?


当前回答

var today = new Date();  //gets current date and time
var hour = today.getHours();         
var minute = today.getMinutes();
var second = today.getSeconds();

其他回答

看看这些Date方法…

更大字符串- https://开发者.mozilla.org/en- us/web /javascrips/web/javascript/javascript / global_objects/date/愚蠢的字符串 totime弦- https://开发者.mozllla.org/en - us/docs/web/javascrips/web/javascript/com// global_objects/date/totimeststststststg

getTime() {
      let today = new Date();
      let h = today.getHours();
      let m = today.getMinutes();
      let s = today.getSeconds();
      h = h < 10 ? "0" + h : h;
      m = m < 10 ? "0" + m : m;
      s = s < 10 ? "0" + s : s;
      let time = h + ":" + m + ":" + s;
      return time;
    },

试试这个:

var date = new Date();
var hour = date.getHours();
var min = date.getMinutes();

赋值给变量并显示。

time = new Date();

var hh = time.getHours();
var mm = time.getMinutes();
var ss = time.getSeconds() 

document.getElementById("time").value = hh + ":" + mm + ":" + ss;

简短而简单:

new Date().toLocaleTimeString(); // 11:18:48 AM
//---
new Date().toLocaleDateString(); // 11/16/2015
//---
new Date().toLocaleString(); // 11/16/2015, 11:18:48 PM

4小时后(使用milisec: sec==1000):

new Date(new Date().getTime() + 4*60*60*1000).toLocaleTimeString(); // 3:18:48 PM or 15:18:48

2天前:

new Date(new Date().getTime() - 2*24*60*60*1000).toLocaleDateString() // 11/14/2015