对于Ben Lesh的回答，应该有这样一条线

ng-init="somethingHere = somethingHere || options[0]" 

而不是

ng-init="somethingHere = somethingHere || options[0].value" 

也就是说,

<选择ng-model = " somethingHere " ng-init="somethingHere = somethingHere || options[0]" Ng-options ="option.name for options track by option.value"> < /选择>

Srivathsa Harish Venkataramana只有一个回答提到了轨道，这确实是一个解决方案!

下面是一个关于如何在select ng-options中使用track by的例子(链接如下):

<select ng-model="selectedCity"
        ng-options="city as city.name for city in cities track by city.id">
  <option value="">-- Select City --</option>
</select>

如果selectedCity定义在angular作用域上，并且它的id属性与cities列表中任何城市的id值相同，它将在加载时自动选择。

下面是普伦克的解释: http://plnkr.co/edit/1EVs7R20pCffewrG0EmI?p=preview

有关更多细节，请参阅源代码文档: https://code.angularjs.org/1.3.15/docs/api/ng/directive/select

我的解决方案是使用html硬编码我的默认选项。像这样:

HAML:

%select{'ng-model' => 'province', 'ng-options' => "province as province for province in summary.provinces", 'chosen' => "chosen-select", 'data-placeholder' => "BC & ON"}
  %option{:value => "", :selected => "selected"}
    BC & ON

在HTML中:

<select ng-model="province" ng-options="province as province for province in summary.provinces" chosen="chosen-select" data-placeholder="BC & ON">
  <option value="" selected="selected">BC &amp; ON</option>
</select>

我想我的默认选项从我的api返回所有的值，这就是为什么我有一个空白值。也请原谅我的笨手笨脚。我知道这不是对OP问题的直接回答，但人们在谷歌上找到了这个。希望这能帮助到其他人。

这对我很管用。

<select ng-model="somethingHere" ng-init="somethingHere='Cool'">
    <option value="Cool">Something Cool</option>
    <option value="Else">Something Else</option>
</select>

试试这个:

HTML

<select 
    ng-model="selectedOption" 
    ng-options="option.name for option in options">
</select>

Javascript

function Ctrl($scope) {
    $scope.options = [
        {
          name: 'Something Cool',
          value: 'something-cool-value'
        }, 
        {
          name: 'Something Else',
          value: 'something-else-value'
        }
    ];

    $scope.selectedOption = $scope.options[0];
}

砰砰作响。

如果您真的想设置将绑定到模型的值，那么将ng-options属性更改为

ng-options="option.value as option.name for option in options"

和Javascript

...
$scope.selectedOption = $scope.options[0].value;

考虑到上述情况，这里又一个普伦克。

您可以像这样简单地使用ng-init

<select ng-init="somethingHere = options[0]" 
        ng-model="somethingHere" 
        ng-options="option.name for option in options">
</select>