以下内容可能会帮到你:

-(NSArray *)tableView:(UITableView *)tableView editActionsForRowAtIndexPath:(NSIndexPath *)indexPath {
    UITableViewRowAction *button = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 1" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
    {
        NSLog(@"Action to perform with Button 1");
    }];
    button.backgroundColor = [UIColor greenColor]; //arbitrary color
    UITableViewRowAction *button2 = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 2" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
                                    {
                                        NSLog(@"Action to perform with Button2!");
                                    }];
    button2.backgroundColor = [UIColor blueColor]; //arbitrary color

    return @[button, button2]; //array with all the buttons you want. 1,2,3, etc...
}

- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath {
    // you need to implement this method too or nothing will work:
}

- (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath {
    return YES; //tableview must be editable or nothing will work...
}

我创建了一个新的库来实现可滑动的按钮，它支持各种过渡和可扩展的按钮，如iOS 8邮件应用程序。

https://github.com/MortimerGoro/MGSwipeTableCell

这个库兼容所有创建UITableViewCell的不同方法，它在iOS 5、iOS 6、iOS 7和iOS 8上进行了测试。

以下是一些过渡的例子:

边境的转变:

夹过渡

3 d的转变:

为了改进Johnny的回答，现在可以使用下面的公共API来完成:

func tableView(tableView: UITableView, editActionsForRowAtIndexPath indexPath: NSIndexPath) -> [UITableViewRowAction]? {

    let moreRowAction = UITableViewRowAction(style: UITableViewRowActionStyle.default, title: "More", handler:{action, indexpath in
        print("MORE•ACTION");
    });
    moreRowAction.backgroundColor = UIColor(red: 0.298, green: 0.851, blue: 0.3922, alpha: 1.0);

    let deleteRowAction = UITableViewRowAction(style: UITableViewRowActionStyle.default, title: "Delete", handler:{action, indexpath in
        print("DELETE•ACTION");
    });

    return [deleteRowAction, moreRowAction];
}

以下内容可能会帮到你:

-(NSArray *)tableView:(UITableView *)tableView editActionsForRowAtIndexPath:(NSIndexPath *)indexPath {
    UITableViewRowAction *button = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 1" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
    {
        NSLog(@"Action to perform with Button 1");
    }];
    button.backgroundColor = [UIColor greenColor]; //arbitrary color
    UITableViewRowAction *button2 = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 2" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
                                    {
                                        NSLog(@"Action to perform with Button2!");
                                    }];
    button2.backgroundColor = [UIColor blueColor]; //arbitrary color

    return @[button, button2]; //array with all the buttons you want. 1,2,3, etc...
}

- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath {
    // you need to implement this method too or nothing will work:
}

- (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath {
    return YES; //tableview must be editable or nothing will work...
}

约翰尼的答案是正确的。我只是在objective-c中添加了下面的代码，以便初学者(以及那些拒绝学习Swift语法的人:)

确保你声明了uitableviewdelegate并拥有以下方法:

 -(NSArray *)tableView:(UITableView *)tableView editActionsForRowAtIndexPath:(NSIndexPath *)indexPath {
 UITableViewRowAction *button = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 1" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
    {
        NSLog(@"Action to perform with Button 1");
    }];
    button.backgroundColor = [UIColor greenColor]; //arbitrary color
    UITableViewRowAction *button2 = [UITableViewRowAction rowActionWithStyle:UITableViewRowActionStyleDefault title:@"Button 2" handler:^(UITableViewRowAction *action, NSIndexPath *indexPath)
                                    {
                                        NSLog(@"Action to perform with Button2!");
                                    }];
    button2.backgroundColor = [UIColor blueColor]; //arbitrary color

    return @[button, button2]; //array with all the buttons you want. 1,2,3, etc...
}

- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath {
// you need to implement this method too or nothing will work:

}
 - (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath
    {
        return YES; //tableview must be editable or nothing will work...
    }

Swift 3实际回答

这是你唯一需要的功能。对于自定义操作，您不需要CanEdit或CommitEditingStyle函数。

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {
    let action1 = UITableViewRowAction(style: .default, title: "Action1", handler: {
        (action, indexPath) in
        print("Action1")
    })
    action1.backgroundColor = UIColor.lightGray
    let action2 = UITableViewRowAction(style: .default, title: "Action2", handler: {
        (action, indexPath) in
        print("Action2")
    })
    return [action1, action2]
}