我正在用Node.js和mongoose写一个web应用程序。如何对我从.find()调用得到的结果进行分页?我想要一个功能可比的“限制50,100”在SQL。
当前回答
这是一个示例函数,用于获得具有分页和限制选项的技能模型的结果
export function get_skills(req, res){
console.log('get_skills');
var page = req.body.page; // 1 or 2
var size = req.body.size; // 5 or 10 per page
var query = {};
if(page < 0 || page === 0)
{
result = {'status': 401,'message':'invalid page number,should start with 1'};
return res.json(result);
}
query.skip = size * (page - 1)
query.limit = size
Skills.count({},function(err1,tot_count){ //to get the total count of skills
if(err1)
{
res.json({
status: 401,
message:'something went wrong!',
err: err,
})
}
else
{
Skills.find({},{},query).sort({'name':1}).exec(function(err,skill_doc){
if(!err)
{
res.json({
status: 200,
message:'Skills list',
data: data,
tot_count: tot_count,
})
}
else
{
res.json({
status: 401,
message: 'something went wrong',
err: err
})
}
}) //Skills.find end
}
});//Skills.count end
}
其他回答
app.get("/:page",(req,res)=>{
post.find({}).then((data)=>{
let per_page = 5;
let num_page = Number(req.params.page);
let max_pages = Math.ceil(data.length/per_page);
if(num_page == 0 || num_page > max_pages){
res.render('404');
}else{
let starting = per_page*(num_page-1)
let ending = per_page+starting
res.render('posts', {posts:data.slice(starting,ending), pages: max_pages, current_page: num_page});
}
});
});
let page,limit,skip,lastPage, query;
page = req.params.page *1 || 1; //This is the page,fetch from the server
limit = req.params.limit * 1 || 1; // This is the limit ,it also fetch from the server
skip = (page - 1) * limit; // Number of skip document
lastPage = page * limit; //last index
counts = await userModel.countDocuments() //Number of document in the collection
query = query.skip(skip).limit(limit) //current page
const paginate = {}
//For previous page
if(skip > 0) {
paginate.prev = {
page: page - 1,
limit: limit
}
//For next page
if(lastPage < counts) {
paginate.next = {
page: page + 1,
limit: limit
}
results = await query //Here is the final results of the query.
使用ts-mongoose-pagination
const trainers = await Trainer.paginate(
{ user: req.userId },
{
perPage: 3,
page: 1,
select: '-password, -createdAt -updatedAt -__v',
sort: { createdAt: -1 },
}
)
return res.status(200).json(trainers)
**//localhost:3000/asanas/?pageNo=1&size=3**
//requiring asanas model
const asanas = require("../models/asanas");
const fetchAllAsanasDao = () => {
return new Promise((resolve, reject) => {
var pageNo = parseInt(req.query.pageNo);
var size = parseInt(req.query.size);
var query = {};
if (pageNo < 0 || pageNo === 0) {
response = {
"error": true,
"message": "invalid page number, should start with 1"
};
return res.json(response);
}
query.skip = size * (pageNo - 1);
query.limit = size;
asanas
.find(pageNo , size , query)
.then((asanasResult) => {
resolve(asanasResult);
})
.catch((error) => {
reject(error);
});
});
}
以上回答是正确的。
只是一个插件,任何人谁是异步等待而不是 承诺! !
const findAllFoo = async (req, resp, next) => {
const pageSize = 10;
const currentPage = 1;
try {
const foos = await FooModel.find() // find all documents
.skip(pageSize * (currentPage - 1)) // we will not retrieve all records, but will skip first 'n' records
.limit(pageSize); // will limit/restrict the number of records to display
const numberOfFoos = await FooModel.countDocuments(); // count the number of records for that model
resp.setHeader('max-records', numberOfFoos);
resp.status(200).json(foos);
} catch (err) {
resp.status(500).json({
message: err
});
}
};
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