尝试得到react-router (v4.0.0)和react-hot loader (3.0.0-beta.6)很好地发挥,但在浏览器控制台得到以下错误:

Warning: React.createElement: type is invalid -- expected a string
(for built-in components) or a class/function (for composite
components) but got: undefined. You likely forgot to export your
component from the file it's defined in.

index.js:

import React from 'react';
import ReactDom from 'react-dom';
import routes from './routes.js';
require('jquery');
import 'bootstrap/dist/css/bootstrap.min.css';
import 'bootstrap/dist/js/bootstrap.min.js';
import './css/main.css';

const renderApp = (appRoutes) => {
    ReactDom.render(appRoutes, document.getElementById('root'));
};

renderApp( routes() );

routes.js:

import React from 'react';
import { AppContainer } from 'react-hot-loader';
import { Router, Route, browserHistory, IndexRoute } from 'react-router';
import store from './store/store.js';
import { Provider } from 'react-redux';
import App from './containers/App.jsx';
import Products from './containers/shop/Products.jsx';
import Basket from './containers/shop/Basket.jsx';

const routes = () => (

    <AppContainer>
        <Provider store={store}>
            <Router history={browserHistory}>
                <Route path="/" component={App}>
                    <IndexRoute component={Products} />
                    <Route path="/basket" component={Basket} />
                </Route>
            </Router>
        </Provider>
    </AppContainer>

);

export default routes;

当前回答

如果在测试组件时出现此错误,请确保每个子组件在单独运行时都能正确呈现,如果其中一个子组件依赖于外部资源来呈现,请尝试使用jest或任何其他mock库来模拟它:

示例:

jest.mock('pathToChildComponent', () => 'mock-child-component')

其他回答

您需要了解命名导出和默认导出。我什么时候应该用大括号导入ES6 ?

在我的例子中,我通过改变

import Provider from 'react-redux'

to

import { Provider } from 'react-redux'

这是一个在某种程度上必须调试的错误。正如已经说过很多次,不恰当的导入/导出会导致这个错误,但令人惊讶的是,我从我的react-router-dom认证设置中的一个小错误中得到了这个错误,下面是我的情况:

错误的设置:

const PrivateRoute = ({ component: Component, ...rest }) => (
    <Route
        {...rest}
        render={(props) => (token ? <Component {...props} /> : <Redirect to={{ pathname: "/login" }} />)}
    />
);

正确设置:

const PrivateRoute = ({ component: Component, token, ...rest }) => (
    <Route
        {...rest}
        render={(props) => (token ? <Component {...props} /> : <Redirect to={{ pathname: "/login" }} />)}
    />
);

唯一的区别是我在PrivateRoute组件中解构了令牌。顺便说一下,令牌是从localstorage获取的,像这样const token = localstorage . getitem ("authUser");所以如果它不在那里,我知道用户没有验证。这也会导致错误。

对我来说,删除Switch解决了这个问题

import React from "react";
import "./styles.css";
import { Route, BrowserRouter, Routes } from "react-router-dom";
import LoginPage from "./pages/LoginPage";
import HomePage from "./pages/HomePage";

export default function App() {
  return (
    <BrowserRouter>
      <Routes>
        <Route exact path="/" element={<HomePage />} />
        <Route path="/login" element={<LoginPage />} />
      </Routes>
    </BrowserRouter>
  );
}

我所缺少的是我正在使用

import { Router, Route, browserHistory, IndexRoute } from 'react-router';

正确答案应该是:

import { BrowserRouter as Router, Route } from 'react-router-dom';

当然你需要添加npm包react-router-dom:

npm install react-router-dom@next --save

简而言之,不知何故发生了以下情况:

render() {
    return (
        <MyComponent /> // MyComponent is undefined.
    );
}

它不一定与某些不正确的输入或输出有关:

render() {
    // MyComponent may be undefined here, for example.
    const MyComponent = this.wizards[this.currentStep];

    return (
        <MyComponent />
    );
}