基本上,我有一个react组件,它的render()函数体如下所示:(这是我的理想之一,这意味着它目前不工作)

render(){
    return (
        <div>
            <Element1/>
            <Element2/>

            // note: logic only, code does not work here
            if (this.props.hasImage) <ElementWithImage/>
            else <ElementWithoutImage/>

        </div>
    )
}

当前回答

你也可以写If语句组件。这是我在我的项目中使用的。

组件/ IfStatement.tsx

import React from 'react'

const defaultProps = {
    condition: undefined,
}

interface IfProps {
    children: React.ReactNode
    condition: any
}

interface StaticComponents {
    Then: React.FC<{ children: any }>
    Else: React.FC<{ children: any }>
}

export function If({ children, condition }: IfProps): any & StaticComponents {
    if (React.Children.count(children) === 1) {
        return condition ? children : null
    }

    return React.Children.map(children as any, (element: React.ReactElement) => {
        const { type: Component }: any = element

        if (condition) {
            if (Component.type === 'then') {
                return element
            }
        } else if (Component.type === 'else') {
            return element
        }

        return null
    })
}

If.defaultProps = defaultProps

export function Then({ children }: { children: any }) {
    return children
}

Then.type = 'then'

export function Else({ children }: { children: any }) {
    return children
}

Else.type = 'else'

If.Then = Then as React.FC<{ children: any }>
If.Else = Else as React.FC<{ children: any }>

export default If

使用的例子:

<If condition={true}>
   <If.Then>
        <div>TRUE</div>
   </If.Then>
   <If.Else>
        <div>NOT TRUE</div>
   </If.Else>
</If>

其他回答

是的,你可以在JSX渲染中使用条件。你可以在这里阅读更多。

语法:

condition ? exprIfTrue : exprIfFalse

条件声明必须如下所示,这里有一个例子:

return (
    <div>
      {condition  ? (
        //do some actions if condition is true
      ) : (
        //do some actions if condition is false
      )}
    </div>
)

if then的简写

 { condition ? <Element1/> : null }

你可以使用if, else这样的条件语句来呈现任何东西:

 render() {
    const price = this.state.price;
    let comp;

    if (price) {

      comp = <h1>Block for getting started with {this.state.price}</h1>

    } else {

      comp = <h1>Block for getting started.</h1>

    }

    return (
      <div>
        <div className="gettingStart">
          {comp}
        </div>
      </div>
    );
  }

我不认为我看到这个解决方案的内联else if渲染,你有超过2个条件,所以我分享它:

{variable == 0 ?
  <Element1/>
:variable == 1 ?
  <Element2/>
:variable == 2 ?
  <Element3/>
:
  <Element4/>
}

你可以引入一个单独的方法来返回div元素并在return中调用它。我使用这种情况的例子,错误呈现取决于状态,如:

const renderError = () => {
    if (condition)
        return ....;
    else if (condition)
        return ....;
    else if (condition)
        return ....;
    else
        return ....;
}

render(){
   return (
     <div>
      ....
      {renderError()}
     </div>
   );
}