我也面临着同样的问题，并决定在TS中使用字符串操作。

如果没有足够的小数，它将返回原始值

const getDecimalsWithoutRounding = (value: number, numberOfDecimals: number) => {
  const stringValue: string = value?.toString();
  const dotIdx: number = stringValue?.indexOf('.');
  if (dotIdx) {
    return parseFloat(stringValue.slice(0, dotIdx + numberOfDecimals + 1));
  } else {
    return value;
  }
};

console.log(getDecimalsWithoutRounding(3.34589, 2)); /// 3.34
console.log(getDecimalsWithoutRounding(null, 2));  ///null
console.log(getDecimalsWithoutRounding(55.123456789, 5)); /// 55.12345
console.log(getDecimalsWithoutRounding(10, 2));  /// 10
console.log(getDecimalsWithoutRounding(10.6, 5)); /// 10.6

下面是一种简单的方法，但必须确保amount参数以字符串形式给出。

function truncate(amountAsString, decimals = 2){
  var dotIndex = amountAsString.indexOf('.');
  var toTruncate = dotIndex !== -1  && ( amountAsString.length > dotIndex + decimals + 1);
  var approach = Math.pow(10, decimals);
  var amountToTruncate = toTruncate ? amountAsString.slice(0, dotIndex + decimals +1) : amountAsString;  
  return toTruncate
    ?  Math.floor(parseFloat(amountToTruncate) * approach ) / approach
    :  parseFloat(amountAsString);

}

console.log(truncate("7.99999")); //OUTPUT ==> 7.99
console.log(truncate("7.99999", 3)); //OUTPUT ==> 7.999
console.log(truncate("12.799999999999999")); //OUTPUT ==> 7.99

function limitDecimalsWithoutRounding(val, decimals){
    let parts = val.toString().split(".");
    return parseFloat(parts[0] + "." + parts[1].substring(0, decimals));
}

var num = parseFloat(15.7784514);
var new_num = limitDecimalsWithoutRounding(num, 2);

我的解决方案在typescript(可以很容易地移植到JS):

/**
 * Returns the price with correct precision as a string
 *
 * @param   price The price in decimal to be formatted.
 * @param   decimalPlaces The number of decimal places to use
 * @return  string The price in Decimal formatting.
 */
type toDecimal = (price: number, decimalPlaces?: number) => string;
const toDecimalOdds: toDecimal = (
  price: number,
  decimalPlaces: number = 2,
): string => {
  const priceString: string = price.toString();
  const pointIndex: number = priceString.indexOf('.');

  // Return the integer part if decimalPlaces is 0
  if (decimalPlaces === 0) {
    return priceString.substr(0, pointIndex);
  }

  // Return value with 0s appended after decimal if the price is an integer
  if (pointIndex === -1) {
    const padZeroString: string = '0'.repeat(decimalPlaces);

    return `${priceString}.${padZeroString}`;
  }

  // If numbers after decimal are less than decimalPlaces, append with 0s
  const padZeroLen: number = priceString.length - pointIndex - 1;
  if (padZeroLen > 0 && padZeroLen < decimalPlaces) {
    const padZeroString: string = '0'.repeat(padZeroLen);

    return `${priceString}${padZeroString}`;
  }

  return priceString.substr(0, pointIndex + decimalPlaces + 1);
};

测试用例:

  expect(filters.toDecimalOdds(3.14159)).toBe('3.14');
  expect(filters.toDecimalOdds(3.14159, 2)).toBe('3.14');
  expect(filters.toDecimalOdds(3.14159, 0)).toBe('3');
  expect(filters.toDecimalOdds(3.14159, 10)).toBe('3.1415900000');
  expect(filters.toDecimalOdds(8.2)).toBe('8.20');

任何改善吗?

function toFixed(num, fixed) {
    fixed = fixed || 0;
    var front = Math.floor(num);
    var back = 0;
    for (var i = 1; i <= fixed; i++) {
        var value = Math.floor(num * Math.pow(10, i)) % 10;
        back += value / Math.pow(10, i);
    }
    return front + back;
}

2016年11月5日更新

新的答案，总是准确的

function toFixed(num, fixed) {
    var re = new RegExp('^-?\\d+(?:\.\\d{0,' + (fixed || -1) + '})?');
    return num.toString().match(re)[0];
}

由于javascript中的浮点数学总是有边缘情况，所以之前的解决方案在大多数情况下都是准确的，这是不够的。 有一些解决方案，如num.toPrecision, BigDecimal.js和accounting.js。 然而，我相信仅仅解析字符串是最简单的，而且总是准确的。

基于@Gumbo接受的答案的良好编写的正则表达式的更新，这个新的toFixed函数将始终按预期工作。

老答案，并不总是准确的。

固定功能:

function toFixed(num, fixed) {
    fixed = fixed || 0;
    fixed = Math.pow(10, fixed);
    return Math.floor(num * fixed) / fixed;
}