Spring引导——不是托管类型

我使用Spring boot+JPA，在启动服务时遇到了一个问题。

Caused by: java.lang.IllegalArgumentException: Not an managed type: class com.nervytech.dialer.domain.PhoneSettings
    at org.hibernate.jpa.internal.metamodel.MetamodelImpl.managedType(MetamodelImpl.java:219)
    at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:68)
    at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:65)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:145)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:89)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:69)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:177)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:239)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:225)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1625)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1562)

这是Application.java文件，

@Configuration
@ComponentScan
@EnableAutoConfiguration(exclude = { DataSourceAutoConfiguration.class })
@SpringBootApplication
public class DialerApplication {

    public static void main(String[] args) {
        SpringApplication.run(DialerApplication.class, args);
    }
}

我使用UCp进行连接池，数据源配置如下:

@Configuration
@ComponentScan
@EnableTransactionManagement
@EnableAutoConfiguration
@EnableJpaRepositories(entityManagerFactoryRef = "dialerEntityManagerFactory", transactionManagerRef = "dialerTransactionManager", basePackages = { "com.nervy.dialer.spring.jpa.repository" })
public class ApplicationDataSource {

    /** The Constant LOGGER. */
    private static final Logger LOGGER = LoggerFactory
            .getLogger(ApplicationDataSource.class);

    /** The Constant TEST_SQL. */
    private static final String TEST_SQL = "select 1 from dual";

    /** The pooled data source. */
    private PoolDataSource pooledDataSource;

UserDetailsService实现,

@Service("userDetailsService")
@SessionAttributes("user")
public class UserDetailsServiceImpl implements UserDetailsService {

    @Autowired
    private UserService userService;

服务层实现，

@Service
public class PhoneSettingsServiceImpl implements PhoneSettingsService {

}

存储库类，

@Repository
public interface PhoneSettingsRepository extends JpaRepository<PhoneSettings, Long> {

}

实体类,

@Entity
@Table(name = "phone_settings", catalog = "dialer")
public class PhoneSettings implements java.io.Serializable {

WebSecurityConfig类,

@Configuration
@EnableWebMvcSecurity
@ComponentScan
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsServiceImpl userDetailsService;

    /**
     * Instantiates a new web security config.
     */
    public WebSecurityConfig() {

        super();
    }

    /**
     * {@inheritDoc}
     * @see org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter#configure(org.springframework.security.config.annotation.web.builders.HttpSecurity)
     */
    @Override
    protected void configure(HttpSecurity http) throws Exception {

        http.authorizeRequests()
            .antMatchers("/login", "/logoffUser", "/sessionExpired", "/error", "/unauth", "/redirect", "*support*").permitAll()
            .anyRequest().authenticated().and().rememberMe().and().httpBasic()
            .and()
            .csrf()
            .disable().logout().deleteCookies("JSESSIONID").logoutSuccessUrl("/logoff").invalidateHttpSession(true);
    }


    @Autowired
    public void configAuthentication(AuthenticationManagerBuilder auth) throws Exception {

      auth.userDetailsService(userDetailsService).passwordEncoder(new BCryptPasswordEncoder());
    }

}

包装如下:

应用程序类在- com. nerve .dialer中数据源类在- com. nerver .dialer.common中实体类在- com. nerver .dialer.domain 服务类在- com.nervy.dialer.domain.service.impl 控制器在- com.nervy.dialer.spring.controller 存储库类在- com.nervy.dialer.spring.jpa.repository中 WebSecurityConfig在- com.nervy.dialer.spring.security

谢谢

当前回答

不要像我一样犯明显的错误，让模板类型的顺序不正确。确保你在模板声明中没有把id放在前面，比如:

public interface CapacityBasedProductRepository extends JpaRepository<Long, CapacityBasedProduct> {
}

JPA类是第一个，id列类型是第二个，如下所示:

public interface CapacityBasedProductRepository extends JpaRepository<CapacityBasedProduct, Long> {
}

否则，它会抱怨java.lang.Long是一个未知的实体类型。它使用第一项查找要使用的实体。

2021-12-02 18:06:34

其他回答

我在spring boot v1.3.x版本中遇到了同样的问题我所做的就是将spring boot升级到1.5.7.RELEASE版本。然后问题就解决了。

2017-11-01 02:53:44

在我的案例中，问题是由于我忘记用@javax.persistence注释我的Entity类。实体注释。哎!

//The class reported as "not a amanaged type"
@javax.persistence.Entity
public class MyEntityClass extends my.base.EntityClass {
    ....
}

2016-09-29 12:05:22

对于未来的读者:

下面是用于扫描多个包的语法糖。

注意，我的两个包也在不同的jar中，但是包是主要的驱动程序。只是在记录我的两罐情况。

    em.setPackagesToScan(new String[] {"com.package.ONE.jpa.entities" , "com.package.TWO.jpa.entities"});

我原来的ERRANT代码如下:

    em.setPackagesToScan("com.package.ONE.jpa.entities, com.package.TWO.jpa.entities");

让我困惑的是我的“xml到java配置切换”。下面显示了一个简单的用逗号分隔的值。

逗号分隔的列表似乎适用于di.xml，但不适用于“java config”。

Java，它是:::"当它是逗号分隔，当它是字符串数组，当它是字符串变参数".......吉格锯拼图有时会把我逼疯。

    <!-- the value of "id" attribute below MUST BE "entityManagerFactory"  spring-data voodoo -->
    <bean id="entityManagerFactory"
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="packagesToScan" value="com.package.ONE.jpa.entities, com.package.TWO.jpa.entities"/>
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="showSql" value="${spring.jpa.show-sql}"/>
                <property name="generateDdl" value="${spring.jpa.generate-ddl}"/>
            </bean>
        </property>
        <!-- See https://stackoverflow.com/questions/16088112/how-to-auto-detect-entities-in-jpa-2-0/16088340#16088340 -->
        <property name="jpaProperties">
            <props>
                <prop key="hibernate.hbm2ddl.auto">${spring.jpa.hibernate.ddl-auto}</prop>
                <prop key="hibernate.dialect">${spring.jpa.properties.hibernate.dialect}</prop>
            </props>
        </property>
    </bean>

2021-03-29 21:59:49

我得到这个错误是因为我愚蠢地写了

公共接口FooBarRepository扩展CrudRepository<FooBarRepository, Long>{…

A brief explanation: One typically creates a FooBarRepository class to manage FooBar objects (often representing data in a table called something like foo_bar.) When extending the CrudRepository to create the specialized repository class, one needs to specify the type that's being managed -- in this case, FooBar. What I mistakenly typed, though, was FooBarRepository rather than FooBar. FooBarRepository is not the type (the class) I'm trying to manage with the FooBarRepository. Therefore, the compiler issues this error.

我用粗体突出显示了输入错误的地方。在我的示例中删除突出显示的单词Repository，代码将被编译。

2019-09-25 18:32:25

如果你配置了你自己的EntityManagerFactory Bean，或者如果你从另一个项目复制粘贴了这样一个持久性配置，你必须在EntityManagerFactory的配置中设置或调整包:

@Bean
public EntityManagerFactory entityManagerFactory() throws PropertyVetoException {
    HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
    vendorAdapter.setGenerateDdl(true);
    LocalContainerEntityManagerFactoryBean factory;
    factory = new LocalContainerEntityManagerFactoryBean();
    factory.setPackagesToScan("!!!!!!package.path.to.entities!!!!!");
    //...
}

注意“多重”需求，你需要一个String数组作为传递给setPackagesToScan的参数(而不是一个逗号分隔的单字符串值)。下面说明了这个问题。

    String[] packagesArray = "com.mypackage1,com.mypackage2".split(",");
    em.setPackagesToScan(packagesArray);

2019-02-19 10:56:25

Spring引导——不是托管类型

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