你在css中设置高度了吗?如果你没有，你需要使用offsetHeight;而不是身高

var h = document.getElementById('someDiv').style.offsetHeight;

你在css中设置高度了吗?如果你没有，你需要使用offsetHeight;而不是身高

var h = document.getElementById('someDiv').style.offsetHeight;

如果我正确理解了你的问题，那么也许这样做会有所帮助:

function testDistance(node1, node2) {
    /* get top position of node 1 */
    let n1Pos = node1.offsetTop;
    /* get height of node 1 */
    let n1Height = node1.clientHeight;
    /* get top position of node 2 */
    let n2Pos = node2.offsetTop;
    /* get height of node 2 */
    let n2Height = node2.clientHeight;

    /* add height of both nodes */
    let heightTogether = n1Height + n2Height;
    /* calculate distance from top of node 1 to bottom of node 2 */
    let actualDistance = (n2Pos + n2Height) - n1Pos;

    /* if the distance between top of node 1 and bottom of node 2
       is bigger than their heights combined, than there is something between them */
    if (actualDistance > heightTogether) {
        /* do something here if they are not together */
        console.log('they are not together');
    } else {
        /* do something here if they are together */
        console.log('together');
    } 
}

它应该只是

$('#someDiv').height();

与jQuery。这将以数字的形式检索换行集中第一项的高度。

尝试使用

.style.height

只有在您首先设置了该属性时才有效。不是很有用!

style = window.getComputedStyle(your_element);

然后简单地:style.height

document.querySelector('.project_list_div').offsetHeight;