试试这个:

i=new Array("aaaa", "bbbb");
j=new Array("cccc", "dddd");

i=i.concat(j);

[].concat.apply([], [array1, array2, ...])

效率证明:http://jsperf.com/multi-array-concat/7

Tim Supinie mentions in the comments that this may cause the interpreter to exceed the call stack size. This is perhaps dependent on the js engine, but I've also gotten "Maximum call stack size exceeded" on Chrome at least. Test case: [].concat.apply([], Array(300000).fill().map(_=>[1,2,3])). (I've also gotten the same error using the currently accepted answer, so one is anticipating such use cases or building a library for others, special testing may be necessary no matter which solution you choose.)

其中'n'是数组的个数，可能是数组的数组…

Var答案= _。Reduce (n, function(a, b){返回a.concat(b)})

现在我们可以使用ES6 Spread组合多个数组。 不要使用concat()来连接数组，而是尝试使用spread语法将多个数组组合成一个扁平数组。 例如:

var a = [1,2];
var b = [3,4];
var c = [5,6,7];
var d = [...a, ...b, ...c];
// resulting array will be like d = [1,2,3,4,5,6,7]

轻松使用concat函数:

var a = [1,2,3];
var b = [2,3,4];
a = a.concat(b);
>> [1,2,3,2,3,4]

concat()方法用于连接两个或多个数组。它不会更改现有数组，只返回已连接数组的副本。

array1 = array1.concat(array2, array3, array4, ..., arrayN);