什么是最简单的方法从android.net.Uri对象持有一个文件:类型转换为java.io.File对象在Android?

我尝试了下面的方法,但不管用:

File file = new File(Environment.getExternalStorageDirectory(), "read.me");
Uri uri = Uri.fromFile(file);
File auxFile = new File(uri.toString());
assertEquals(file.getAbsolutePath(), auxFile.getAbsolutePath());

当前回答

通过下面的代码,我能够获得adobe应用程序共享pdf文件作为流,并保存到android应用程序路径

Android.Net.Uri fileuri =
    (Android.Net.Uri)Intent.GetParcelableExtra(Intent.ExtraStream);

    fileuri i am getting as {content://com.adobe.reader.fileprovider/root_external/
                                        data/data/com.adobe.reader/files/Downloads/sample.pdf}

    string filePath = fileuri.Path;

   filePath I am gettings as root_external/data/data/com.adobe.reader/files/Download/sample.pdf

      using (var stream = ContentResolver.OpenInputStream(fileuri))
      {
       byte[] fileByteArray = ToByteArray(stream); //only once you can read bytes from stream second time onwards it has zero bytes

       string fileDestinationPath ="<path of your destination> "
       convertByteArrayToPDF(fileByteArray, fileDestinationPath);//here pdf copied to your destination path
       }
     public static byte[] ToByteArray(Stream stream)
        {
            var bytes = new List<byte>();

            int b;
            while ((b = stream.ReadByte()) != -1)
                bytes.Add((byte)b);

            return bytes.ToArray();
        }

      public static string convertByteArrayToPDF(byte[] pdfByteArray, string filePath)
        {

            try
            {
                Java.IO.File data = new Java.IO.File(filePath);
                Java.IO.OutputStream outPut = new Java.IO.FileOutputStream(data);
                outPut.Write(pdfByteArray);
                return data.AbsolutePath;

            }
            catch (System.Exception ex)
            {
                return string.Empty;
            }
        }

其他回答

uri.toString()给我:"content://com.google.android.apps.nbu.files.provider/1/file%3A%2F%2F%2Fstorage%2Femulated%2F0%2FDownload%2Fbackup.file"

uri.getPath()给我:“/1/文件:///存储/模拟/0/下载/备份文件。”

new File(uri.getPath())给我“/1/ File:/storage/ emululated /0/Download/backup.file”。

所以如果你有一个文件的访问权限,想要避免使用ContentResolver或直接读取文件,答案是:

private String uriToPath( Uri uri )
{
    File backupFile = new File( uri.getPath() );
    String absolutePath = backupFile.getAbsolutePath();
    return absolutePath.substring( absolutePath.indexOf( ':' ) + 1 );
}

为简化回答,跳过错误处理

扩展基于@Jacek kwiecievik回答转换图像uri文件

fun Uri.toImageFile(context: Context): File? {
    val filePathColumn = arrayOf(MediaStore.Images.Media.DATA)
    val cursor = context.contentResolver.query(this, filePathColumn, null, null, null)
    if (cursor != null) {
        if (cursor.moveToFirst()) {
            val columnIndex = cursor.getColumnIndex(filePathColumn[0])
            val filePath = cursor.getString(columnIndex)
            cursor.close()
            return File(filePath)
        }
        cursor.close()
    }
    return null
}

如果我们使用File(uri.getPath()),它将不起作用

如果我们使用扩展从android-ktx,它仍然不能工作,因为 https://github.com/android/android-ktx/blob/master/src/main/java/androidx/core/net/Uri.kt

我是这样做的:

try {
    readImageInformation(new File(contentUri.getPath()));

} catch (IOException e) {
    readImageInformation(new File(getRealPathFromURI(context,
                contentUri)));
}

public static String getRealPathFromURI(Context context, Uri contentUri) {
        String[] proj = { MediaStore.Images.Media.DATA };
        Cursor cursor = context.getContentResolver().query(contentUri, proj,
                null, null, null);
        int column_index = cursor
                .getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        cursor.moveToFirst();
        return cursor.getString(column_index);
}

所以基本上首先我尝试使用一个文件,即相机拍摄的照片,并保存在SD卡上。这对返回的图像不起作用: 意图photoPickerIntent =新的意图(Intent. action_pick); 在这种情况下,需要通过getRealPathFromURI()函数将Uri转换为真实路径。 所以结论是,这取决于你想转换为File的Uri类型。

使用内容解析器获取输入流

InputStream inputStream = getContentResolver().openInputStream(uri);

然后将输入流复制到文件中

FileUtils.copyInputStreamToFile(inputStream, file);

样品使用方法:

private File toFile(Uri uri) throws IOException {
        String displayName = "";
        Cursor cursor = getContentResolver().query(uri, null, null, null, null);

        if(cursor != null && cursor.moveToFirst()){
            try {
                displayName = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
            }finally {
                cursor.close();
            }
        }

        File file =  File.createTempFile(
                FilenameUtils.getBaseName(displayName),
                "."+FilenameUtils.getExtension(displayName)
        );
        InputStream inputStream = getContentResolver().openInputStream(uri);
        FileUtils.copyInputStreamToFile(inputStream, file);
        return file;
    }

使用这个来写入文件,它为我工作时,gif的uri是由GBoard提供的,我必须在我的应用程序数据复制该gif。

    try {
      String destinationFilePath = getExternalFilesDir("gifs") + "/tempFile.txt";
      InputStream inputStream = getContentResolver().openInputStream(uri);
      OutputStream outputStream = new FileOutputStream(destinationFilePath);

      byte[] buffer = new byte[1024];
      int bytesRead;

      while ((bytesRead = inputStream.read(buffer)) != -1) {
        outputStream.write(buffer, 0, bytesRead);
      }

      inputStream.close();
      outputStream.close();
    }
    catch (Exception e) {
      e.printStackTrace();
    }