如何在Python中以不区分大小写的方式比较字符串?
我想使用简单的python代码将常规字符串的比较封装到存储库字符串中。我也想有能力在字典中查找值哈希字符串使用常规的python字符串。
当前回答
我找到了一个干净的解决方案，我正在使用一些固定的文件扩展名。
from pathlib import Path
class CaseInsitiveString(str):
def __eq__(self, __o: str) -> bool:
return self.casefold() == __o.casefold()
GZ = CaseInsitiveString(".gz")
ZIP = CaseInsitiveString(".zip")
TAR = CaseInsitiveString(".tar")
path = Path("/tmp/ALL_CAPS.TAR.GZ")
GZ in path.suffixes, ZIP in path.suffixes, TAR in path.suffixes, TAR == ".tAr"
# (True, False, True, True)
其他回答
def insenStringCompare(s1, s2):
""" Method that takes two strings and returns True or False, based
on if they are equal, regardless of case."""
try:
return s1.lower() == s2.lower()
except AttributeError:
print "Please only pass strings into this method."
print "You passed a %s and %s" % (s1.__class__, s2.__class__)
先转换成小写字母怎么样?你可以使用string.lower()。
通常的方法是将字符串大写或小写，以便进行查找和比较。例如:
>>> "hello".upper() == "HELLO".upper()
True
>>>
你可以在str.contains()中提到case=False
data['Column_name'].str.contains('abcd', case=False)
假设ASCII字符串:
string1 = 'Hello'
string2 = 'hello'
if string1.lower() == string2.lower():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")
从Python 3.3开始，casefold()是一个更好的选择:
string1 = 'Hello'
string2 = 'hello'
if string1.casefold() == string2.casefold():
print("The strings are the same (case insensitive)")
else:
print("The strings are NOT the same (case insensitive)")
如果您想要一个处理更复杂unicode比较的更全面的解决方案，请参阅其他答案。
