真的，我不明白为什么不能用

arr = arr.filter(value => value !== 'seven');

或者你可能想使用普通的JS

arr = arr.filter(function(value) { return value !== 'seven' });

请不要使用带有delete的变体-它会在数组中留下一个洞，因为它不会在删除的项之后重新索引元素。

> Array.prototype.remove=function(v){
...     delete this[this.indexOf(v)]
... };
[Function]
> var myarray=["3","24","55","2"];
undefined
> myarray.remove("55");
undefined
> myarray
[ '3', '24', , '2' ]

你可以使用lodash的拉函数

Var ary = [' 3 '， ' 7 '， ' 11 ']; _。拉(氩,' 7 ');// [' 3 '， ' 11 '] console.log(必要) < script src = " https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.6.1/lodash.js " > < /脚本>

如果你有唯一的值，顺序不重要，使用Set，它有delete():

var mySet = new Set(['three', 'seven', 'eleven']);
mySet.delete('seven'); // Returns true, successfully removed    
[...mySet];            // Returns ['three', 'eleven']

//This function allows remove even array from array
var removeFromArr = function(arr, elem) { 
    var i, len = arr.length, new_arr = [],
    sort_fn = function (a, b) { return a - b; };
    for (i = 0; i < len; i += 1) {
        if (typeof elem === 'object' && typeof arr[i] === 'object') {
            if (arr[i].toString() === elem.toString()) {
                continue;
            } else {                    
                if (arr[i].sort(sort_fn).toString() === elem.sort(sort_fn).toString()) {
                    continue;
                }
            }
        }
        if (arr[i] !== elem) {
            new_arr.push(arr[i]);
        }
    }
    return new_arr;
}

使用实例

var arr = [1, '2', [1 , 1] , 'abc', 1, '1', 1];
removeFromArr(arr, 1);
//["2", [1, 1], "abc", "1"]

var arr = [[1, 2] , 2, 'a', [2, 1], [1, 1, 2]];
removeFromArr(arr, [1,2]);
//[2, "a", [1, 1, 2]]

ES6路。

const commentsWithoutDeletedArray = commentsArray.filter(comment => comment.Id !== commentId);