如果我在Bash中有一个这样的数组:
FOO=( a b c )
如何用逗号连接元素?例如,生成a b c。
如果我在Bash中有一个这样的数组:
FOO=( a b c )
如何用逗号连接元素?例如,生成a b c。
当前回答
也许我遗漏了一些明显的东西,因为我是bash/zsh的新手,但在我看来,您根本不需要使用printf。没有它也不会变得很难看。
join() {
separator=$1
arr=$*
arr=${arr:2} # throw away separator and following space
arr=${arr// /$separator}
}
至少,到目前为止,它对我来说是有效的。
例如,加入\| *.sh,假设我在~目录下,输出utilities.sh|play.sh|foobar.sh。对我来说足够好了。
编辑:这基本上是Nil Geisweiller的答案,但推广到一个函数。
其他回答
感谢@gniourf_gniourf对我迄今为止的最佳世界组合的详细评论。很抱歉发布的代码没有完全设计和测试。这是一个更好的尝试。
# join with separator
join_ws() { local d=$1 s=$2; shift 2 && printf %s "$s${@/#/$d}"; }
这种概念上的美是
(still) 100% pure bash ( thanks for explicitly pointing out that printf is a builtin as well. I wasn't aware about this before ... ) works with multi-character delimiters more compact and more complete and this time carefully thought over and long-term stress-tested with random substrings from shell scripts amongst others, covering use of shell special characters or control characters or no characters in both separator and / or parameters, and edge cases, and corner cases and other quibbles like no arguments at all. That doesn't guarantee there is no more bug, but it will be a little harder challenge to find one. BTW, even the currently top voted answers and related suffer from such things like that -e bug ...
附加的例子:
$ join_ws '' a b c
abc
$ join_ws ':' {1,7}{A..C}
1A:1B:1C:7A:7B:7C
$ join_ws -e -e
-e
$ join_ws $'\033[F' $'\n\n\n' 1. 2. 3. $'\n\n\n\n'
3.
2.
1.
$ join_ws $
$
awk -v sep=. 'BEGIN{ORS=OFS="";for(i=1;i<ARGC;i++){print ARGV[i],ARGC-i-1?sep:""}}' "${arr[@]}"
or
$ a=(1 "a b" 3)
$ b=$(IFS=, ; echo "${a[*]}")
$ echo $b
1,a b,3
liststr=""
for item in list
do
liststr=$item,$liststr
done
LEN=`expr length $liststr`
LEN=`expr $LEN - 1`
liststr=${liststr:0:$LEN}
这也可以处理结尾多余的逗号。我不是bash专家。只是我的2c,因为这更基本,更容易理解
x = $ {arr [*] / /,)
这是做这件事最短的方法。
的例子,
# ZSH:
arr=(1 "2 3" 4 5)
x=${"${arr[*]}"// /,}
echo $x # output: 1,2,3,4,5
# ZSH/BASH:
arr=(1 "2 3" 4 5)
a=${arr[*]}
x=${a// /,}
echo $x # output: 1,2,3,4,5
下面是大多数POSIX兼容shell支持的一个:
join_by() {
# Usage: join_by "||" a b c d
local arg arr=() sep="$1"
shift
for arg in "$@"; do
if [ 0 -lt "${#arr[@]}" ]; then
arr+=("${sep}")
fi
arr+=("${arg}") || break
done
printf "%s" "${arr[@]}"
}