xs = ['L', 'O', 'L']
lol_string = ''.join(map(str, xs))

xs = ['L', 'O', 'L']
lol_string = ''.join(map(str, xs))

使用“. join:

xs = ['1', '2', '3']
s = ''.join(xs)

如果列表包含整数，则在连接它们之前将元素转换为字符串:

xs = [1, 2, 3]
s = ''.join(str(x) for x in xs)

>>> xs = [1, 2, 3]       
>>> " ".join(str(x) for x in xs)
'1 2 3'