我创建了很好的kotlin-esqe扩展函数，如果有人感兴趣的话

fun Activity.hideKeyBoard() {
    val view = this.currentFocus
    val methodManager = this.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    assert(view != null)
    methodManager.hideSoftInputFromWindow(view!!.windowToken, InputMethodManager.HIDE_NOT_ALWAYS)
}

fun Activity.showKeyboard() {
    val view = this.currentFocus
    val methodManager = this.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    assert(view != null)
    methodManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT)
}

这有点棘手。我这样做了，而且成功了。

1.在第一次调用时，从窗口中隐藏软输入。如果软键盘可见，这将隐藏软输入;如果软键盘不可见，则不执行任何操作。

2.展示你的对话

3.然后简单地调用切换软输入。

代码:

InputMethodManager inputManager = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE); 
//hiding soft input
inputManager.hideSoftInputFromWindow(findViewById(android.R.id.content).getWind‌​owToken(), 0);
//show dialog
yourDialog.show();
//toggle soft input
inputManager.toggleSoftInput(InputMethodManager.SHOW_FORCED,InputMethodManager.SHOW_IMPLICIT);

我找到了这个例子http://android-codes-examples.blogspot.com/2011/11/show-or-hide-soft-keyboard-on-opening.html。在alert.show()之前添加以下代码。

InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
imm.toggleSoftInput(InputMethodManager.SHOW_FORCED,0);

我有同样的问题，并解决了它与以下代码。我不确定它在有硬件键盘的手机上会有什么表现。

// TextEdit
final EditText textEdit = new EditText(this);

// Builder
AlertDialog.Builder alert = new AlertDialog.Builder(this);
alert.setTitle("Enter text");
alert.setView(textEdit);

alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
    @Override
    public void onClick(DialogInterface dialog, int which) {
        String text = textEdit.getText().toString();
        finish();
    }
});

alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
    @Override
    public void onClick(DialogInterface dialog, int which) {
        finish();
    }
});

// Dialog
AlertDialog dialog = alert.create();
dialog.setOnShowListener(new OnShowListener() {

    @Override
    public void onShow(DialogInterface dialog) {
        InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
        imm.showSoftInput(textEdit, InputMethodManager.SHOW_IMPLICIT);
    }
});

dialog.show();

我的方法使用了Android 11+的新方法，也支持旧版本:

fun Fragment.showKeyboard() {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.R) {
        ViewCompat.getWindowInsetsController(requireView())?.show(WindowInsetsCompat.Type.ime())
    } else {
        val focusedView = view?.findFocus() ?: view?.apply { requestFocus() }
        val imm = (context?.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager)
        val isShowSucceeded = imm.showSoftInput(focusedView, InputMethodManager.SHOW_IMPLICIT)
        if(!isShowSucceeded) {
            imm.toggleSoftInputFromWindow(
                view?.windowToken, 0, InputMethodManager.HIDE_IMPLICIT_ONLY)
    }
}

}

尝试了很多，但这对我来说是有效的(kotlin):

        val dialog = builder.create()
        dialog.setOnShowListener {
            nameEditText.requestFocus()
            val s = ContextCompat.getSystemService(requireContext(), InputMethodManager::class.java)
            s?.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0)
        }

        dialog.setOnDismissListener {
            val s = ContextCompat.getSystemService(requireContext(), InputMethodManager::class.java)
            s?.toggleSoftInput(InputMethodManager.HIDE_IMPLICIT_ONLY, 0)
        }

        dialog.show()