我正在使用AlertDialog显示一个输入框。当我调用AlertDialog.show()时,对话框内部的EditText会自动聚焦,但软键盘不会自动显示。
我如何使软键盘自动显示时,对话框显示?(并且没有物理/硬件键盘)。类似于当我按下Search按钮调用全局搜索时,会自动显示软键盘。
我正在使用AlertDialog显示一个输入框。当我调用AlertDialog.show()时,对话框内部的EditText会自动聚焦,但软键盘不会自动显示。
我如何使软键盘自动显示时,对话框显示?(并且没有物理/硬件键盘)。类似于当我按下Search按钮调用全局搜索时,会自动显示软键盘。
当前回答
我创建了很好的kotlin-esqe扩展函数,如果有人感兴趣的话
fun Activity.hideKeyBoard() {
val view = this.currentFocus
val methodManager = this.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
assert(view != null)
methodManager.hideSoftInputFromWindow(view!!.windowToken, InputMethodManager.HIDE_NOT_ALWAYS)
}
fun Activity.showKeyboard() {
val view = this.currentFocus
val methodManager = this.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
assert(view != null)
methodManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT)
}
其他回答
要显示键盘,对我来说,我必须执行以下操作
Android文本字段:设置焦点+软输入编程
基本上解决方案如下
@Override
public void onResume() {
super.onResume();
//passwordInput.requestFocus(); <-- that doesn't work
passwordInput.postDelayed(new ShowKeyboard(), 325); //250 sometimes doesn't run if returning from LockScreen
}
ShowKeyboard在哪里
private class ShowKeyboard implements Runnable {
@Override
public void run() {
passwordInput.setFocusableInTouchMode(true);
//passwordInput.requestFocusFromTouch(); //this gives touch event to launcher in background -_-
passwordInput.requestFocus();
getActivity().getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
((InputMethodManager) getActivity().getSystemService(Context.INPUT_METHOD_SERVICE)).showSoftInput(passwordInput, 0);
}
}
在成功输入之后,我还确保隐藏了键盘
getActivity().getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_HIDDEN);
((InputMethodManager) getActivity().getSystemService(Context.INPUT_METHOD_SERVICE))
.hideSoftInputFromWindow(getView().getWindowToken(), 0);
我有同样的问题,并解决了它与以下代码。我不确定它在有硬件键盘的手机上会有什么表现。
// TextEdit
final EditText textEdit = new EditText(this);
// Builder
AlertDialog.Builder alert = new AlertDialog.Builder(this);
alert.setTitle("Enter text");
alert.setView(textEdit);
alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
String text = textEdit.getText().toString();
finish();
}
});
alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
finish();
}
});
// Dialog
AlertDialog dialog = alert.create();
dialog.setOnShowListener(new OnShowListener() {
@Override
public void onShow(DialogInterface dialog) {
InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
imm.showSoftInput(textEdit, InputMethodManager.SHOW_IMPLICIT);
}
});
dialog.show();
是的,你可以用setOnFocusChangeListener来做,它会帮助你。
editText.setOnFocusChangeListener(new View.OnFocusChangeListener() {
@Override
public void onFocusChange(View v, boolean hasFocus) {
if (hasFocus) {
dialog.getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
}
}
});
在AlertDialog中从EditText显示软键盘的问题可能是在AlertDialog.show()中,因为在显示AlertDialog之后应用了EditText。我不确定所有版本的API都是这样,但我认为解决方案来自API级别21,因为它来自AlertDialog.create(),它应该在AlertDialog.show()之前调用。
这是我对这种情况的最佳解决方案。首先,在某个地方创建:
private int showKeyboard(View view) {
final InputMethodManager inputManager = (InputMethodManager) requireActivity().getSystemService(Context.INPUT_METHOD_SERVICE);
if (inputManager != null) {
boolean isShown = inputManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT); // flag=InputMethodManager.SHOW_IMPLICIT ili =
return (isShown) ? 1: -1;
}
return 0;
}
然后,在AlertDialog之后。生成器生成器= new AlertDialog.Builder(requireContext());继续:
EditText editText = new EditText(requireContext());
builder.setView(editText);
// ... put positive-negative buttons, and etc ...
AlertDialog dialog = builder.create(); // Create dialog from builder
dialog.setCancelable(false); // If you need
Handler handler = new Handler();
dialog.setOnShowListener(new DialogInterface.OnShowListener() {
@Override
public void onShow(DialogInterface dialog) { // 1. When a dialog is displayed
editText.requestFocus();
Runnable runnable = new Runnable() { // create one runnable
int counter = 0;
public void run() {
int status = showKeyboard(editText); // 2. Call func.above for keyboard, but...
if(status == -1 && counter < 10){ handler.postDelayed(this, 100); counter ++; } // ...if it inst shown call again after 100ms
}
};
runnable.run(); // Execute runnable first time here
}
});
dialog.show();
不要忘记导入android.os.Handler;等等;-)
感谢大家的投票。
这对我很有用。我为对话框设置了一个OnShowListener,在那个监听器中,我为文本字段设置了一个onFocusChangeListener,在那个FocusChangeListener中,我用100ms的延迟调用showSoftInput,然后删除FocusChangeListener,所以它只处理第一个焦点变化。
当调用dialog.show()时,OnShowListener被调用,它请求文本字段的焦点。当文本字段获得焦点时,将调用FocusChangeListener并最终显示键盘。
val views = DialogBinding.inflate(layoutInflater) // layout with 'textfield'
val dialog = MaterialAlertDialogBuilder(requireContext())
.setTitle("Exercise")
.setView(views.root)
...
.create()
dialog.setOnShowListener {
views.textfield.onFocusChangeListener = View.OnFocusChangeListener { view, _ ->
view.postDelayed({
(view.context.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager).showSoftInput(view, 0)
}, 100)
views.textfield.onFocusChangeListener = null
}
views.repcount.requestFocus()
}
dialog.show()