如果你曾经使用过JavaScript，你就会知道Internet Explorer没有为Array.prototype.indexOf()[包括Internet Explorer 8]实现ECMAScript函数。这不是一个大问题，因为您可以使用以下代码扩展页面上的功能。
Array.prototype.indexOf = function(obj, start) {
for (var i = (start || 0), j = this.length; i < j; i++) {
if (this[i] === obj) { return i; }
}
return -1;
}
我应该什么时候实现这个?
我是否应该用下面的检查将它包装在我的所有页面上，检查原型函数是否存在，如果不存在，继续扩展数组原型?
if (!Array.prototype.indexOf) {
// Implement function here
}
或者做浏览器检查，如果是ie，就实现它?
//Pseudo-code
if (browser == IE Style Browser) {
// Implement function here
}
有Mozilla官方解决方案:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf
(function() {
/**Array*/
// Production steps of ECMA-262, Edition 5, 15.4.4.14
// Reference: http://es5.github.io/#x15.4.4.14
if (!Array.prototype.indexOf) {
Array.prototype.indexOf = function(searchElement, fromIndex) {
var k;
// 1. Let O be the result of calling ToObject passing
// the this value as the argument.
if (null === this || undefined === this) {
throw new TypeError('"this" is null or not defined');
}
var O = Object(this);
// 2. Let lenValue be the result of calling the Get
// internal method of O with the argument "length".
// 3. Let len be ToUint32(lenValue).
var len = O.length >>> 0;
// 4. If len is 0, return -1.
if (len === 0) {
return -1;
}
// 5. If argument fromIndex was passed let n be
// ToInteger(fromIndex); else let n be 0.
var n = +fromIndex || 0;
if (Math.abs(n) === Infinity) {
n = 0;
}
// 6. If n >= len, return -1.
if (n >= len) {
return -1;
}
// 7. If n >= 0, then Let k be n.
// 8. Else, n<0, Let k be len - abs(n).
// If k is less than 0, then let k be 0.
k = Math.max(n >= 0 ? n : len - Math.abs(n), 0);
// 9. Repeat, while k < len
while (k < len) {
// a. Let Pk be ToString(k).
// This is implicit for LHS operands of the in operator
// b. Let kPresent be the result of calling the
// HasProperty internal method of O with argument Pk.
// This step can be combined with c
// c. If kPresent is true, then
// i. Let elementK be the result of calling the Get
// internal method of O with the argument ToString(k).
// ii. Let same be the result of applying the
// Strict Equality Comparison Algorithm to
// searchElement and elementK.
// iii. If same is true, return k.
if (k in O && O[k] === searchElement) {
return k;
}
k++;
}
return -1;
};
}
})();
