Moment.js中的弃用警告-不是公认的ISO格式

我得到一个警告，提供给moment的值不是公认的ISO格式。今天我用矩函数改变了变量，但它仍然不起作用。

下面是警告错误:

Deprecation warning: value provided is not in a recognized ISO format. moment construction falls back to js Date(), which is not reliable across all browsers and versions. Non ISO date formats are discouraged and will be removed in an upcoming major release. Please refer to http://momentjs.com/guides/#/warnings/js-date/ for more info. Arguments: [0] _isAMomentObject: true, _isUTC: true, _useUTC: true, _l: undefined, _i: 2016-9-26 19:30, _f: undefined, _strict: undefined, _locale: [object Object]

var entryDate = new Date();
var currentDate = entryDate.getDate();

function between(x, min, max) {
  return x.valueOf() >= min.valueOf() && x < max.valueOf();
}

$('#custom1').change(function () {
  if ($('#custom1 :selected').val() == 'AU') {
    var keyword = '';

    var aus1_s = moment.tz('2016-9-26 19:30', 'Australia/Sydney');
    var aus2_s = moment.tz('2016-10-2 19:30', 'Australia/Sydney');
    var aus3_s = moment.tz('2016-10-9 19:30', 'Australia/Sydney');
    var aus4_s = moment.tz('2016-10-16 19:30', 'Australia/Sydney');
    var aus5_s = moment.tz('2016-10-23 19:30', 'Australia/Sydney');
    var aus6_s = moment.tz('2016-10-30 19:30', 'Australia/Sydney');
    var aus6_e = moment.tz('2016-11-5 19:30', 'Australia/Sydney');
  } else if ($('#custom1 :selected').val() == 'NZ') {
    var aus1_s = moment.tz('2016-9-28 20:30', 'Pacific/Auckland');
    var aus2_s = moment.tz('2016-10-4 20:30', 'Pacific/Auckland');
    var aus3_s = moment.tz('2016-10-11 20:30', 'Pacific/Auckland');
    var aus4_s = moment.tz('2016-10-18 20:30', 'Pacific/Auckland');
    var aus5_s = moment.tz('2016-10-25 20:30', 'Pacific/Auckland');
    var aus6_s = moment.tz('2016-11-2 20:30', 'Pacific/Auckland');
    var aus6_e = moment.tz('2016-11-9 20:30', 'Pacific/Auckland');
  } else {
    $('#entryEquals').val('');
    return false;
  }

  var today = moment();

  switch (true) {
    case between(today, aus1_s, aus2_s):
      keyword = 'RElYT04=';
      break;

    case between(today, aus2_s, aus3_s):
      keyword = 'QlJJREU=';
      break;

    case between(today, aus3_s, aus4_s):
      keyword = 'U1lETkVZ';
      break;

    case between(today, aus4_s, aus5_s):
      keyword = 'R1JPT00=';
      break;

    case between(today, aus5_s, aus6_s):
      keyword = 'V0VERElORw==';
      break;

    case between(today, aus6_s, aus6_e):
      keyword = 'VExD';
      break;

    default:
      $('#entryEquals').val('');
      break;
  }

  $('#entryEquals').val(keyword);
});

当前回答

 var nowTime = moment();

 var nowTimeFormate = moment(nowTime).format("HH:mm");

 console.log('from now time',nowTimeFormate)

这种语法帮助我避免警告

2022-05-13 17:59:55

其他回答

像这样在函数中使用矩

let date = "01/11/1992"  // string
moment(new Date(date)).format('MM/DD/YYYY')

2018-08-04 21:10:09

let m = moment(new Date(dateObjectVariable));

我采用了与其他评分答案相似的方法。我注意到我不需要“。format”。此方法用于从moment(new Date(dateObjectVariable))构造函数创建一个moment对象，以便为我的函数操作它。

2022-08-01 17:12:13

const dateFormat = 'MM-DD-YYYY';

const currentDateStringType = moment(new Date()).format(dateFormat);
    
const currentDate = moment(new Date() ,dateFormat);  // use this

的时刻。suppressDeprecationWarnings = true;

2021-02-17 11:42:47

这可能有点迟了。我的问题是我没有从数据库传递的格式(我的是NULL)。

文档说:当传递给string构造函数的日期没有找到已知格式时，抛出此弃用警告。要解决这个问题，请指定传递给moment()的字符串的格式。

2021-12-30 18:58:04

你可以使用

moment(date,"currentFormat").format("requiredFormat");

当date不是ISO格式时，这应该被使用，因为它会告诉moment我们当前的格式是什么。

2020-01-15 07:00:12

Moment.js中的弃用警告-不是公认的ISO格式

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