最短一行

let key = Object.keys(obj).find(k=>obj[k]===value);

返回值为:

let keys = Object.keys(obj).filter(k=>obj[k]===value);

如果value为数组或对象:

let keys = Object.keys(obj).filter(k=>JSON.stringify(obj[k])===JSON.stringify(value));

如前所述，迭代是必要的。例如，在现代浏览器中，你可以有:

var key = Object.keys(obj).filter(function(key) {return obj[key] === value})[0];

value包含了你要找的值。 说到这里，我可能会使用循环。

否则，你可以使用一个合适的“hashmap”对象——在JS中有几个实现——或者你自己实现。

更新2018

六年过去了，但我仍然得到了一些投票，所以我觉得一个更现代的解决方案——适用于现代浏览器/环境——应该在答案中提到，而不仅仅是在评论中:

const key = Object.keys(obj).find(key => obj[key] === value);

当然它也可以是一个函数:

const getKeyByValue = (obj, value) => 
        Object.keys(obj).find(key => obj[key] === value);

http://jsfiddle.net/rTazZ/2/

var a = new Array(); 
    a.push({"1": "apple", "2": "banana"}); 
    a.push({"3": "coconut", "4": "mango"});

    GetIndexByValue(a, "coconut");

    function GetIndexByValue(arrayName, value) {  
    var keyName = "";
    var index = -1;
    for (var i = 0; i < arrayName.length; i++) { 
       var obj = arrayName[i]; 
            for (var key in obj) {          
                if (obj[key] == value) { 
                    keyName = key; 
                    index = i;
                } 
            } 
        }
        //console.log(index); 
        return index;
    } 

这里有一个Lodash解决方案，适用于flat key =>值对象，而不是嵌套对象。已接受的答案建议使用_。findKey适用于具有嵌套对象的对象，但在这种常见情况下不起作用。

这种方法将对象颠倒，将键交换为值，然后通过查找新(颠倒的)对象上的值来查找键。如果没有找到键，则返回false，我更喜欢undefined，但你可以很容易地在_的第三个参数中交换它。getKey()中的get方法。

// Get an object's key by value var getKey = function( obj, value ) { var inverse = _.invert( obj ); return _.get( inverse, value, false ); }; // US states used as an example var states = { "AL": "Alabama", "AK": "Alaska", "AS": "American Samoa", "AZ": "Arizona", "AR": "Arkansas", "CA": "California", "CO": "Colorado", "CT": "Connecticut", "DE": "Delaware", "DC": "District Of Columbia", "FM": "Federated States Of Micronesia", "FL": "Florida", "GA": "Georgia", "GU": "Guam", "HI": "Hawaii", "ID": "Idaho", "IL": "Illinois", "IN": "Indiana", "IA": "Iowa", "KS": "Kansas", "KY": "Kentucky", "LA": "Louisiana", "ME": "Maine", "MH": "Marshall Islands", "MD": "Maryland", "MA": "Massachusetts", "MI": "Michigan", "MN": "Minnesota", "MS": "Mississippi", "MO": "Missouri", "MT": "Montana", "NE": "Nebraska", "NV": "Nevada", "NH": "New Hampshire", "NJ": "New Jersey", "NM": "New Mexico", "NY": "New York", "NC": "North Carolina", "ND": "North Dakota", "MP": "Northern Mariana Islands", "OH": "Ohio", "OK": "Oklahoma", "OR": "Oregon", "PW": "Palau", "PA": "Pennsylvania", "PR": "Puerto Rico", "RI": "Rhode Island", "SC": "South Carolina", "SD": "South Dakota", "TN": "Tennessee", "TX": "Texas", "UT": "Utah", "VT": "Vermont", "VI": "Virgin Islands", "VA": "Virginia", "WA": "Washington", "WV": "West Virginia", "WI": "Wisconsin", "WY": "Wyoming" }; console.log( 'The key for "Massachusetts" is "' + getKey( states, 'Massachusetts' ) + '"' ); <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

没有看到以下内容:

Const obj = { id: 1、 名称:“窝” }; 函数getKeyByValue(obj, value) { 返回Object.entries (obj)。Find (([， name]) => value === name); ｝ const [key] = getKeyByValue(obj， 'Den'); console.log(关键)

或者，更简单的是—按您想要的顺序创建一个具有键和值的新对象，然后查找该对象。我们在使用上面的原型代码时发生了冲突。你不必在键周围使用String函数，那是可选的。

 newLookUpObj = {};
 $.each(oldLookUpObj,function(key,value){
        newLookUpObj[value] = String(key);
    });