使用PowerShell,我想用MyValue替换给定文件中所有精确出现的[MYID]。最简单的方法是什么?


当前回答

我从帕耶特的Windows Powershell in Action中找到了一个鲜为人知但非常酷的方法。您可以像引用变量一样引用文件,类似于$env:path,但需要添加花括号。

${c:file.txt} = ${c:file.txt} -replace 'oldvalue','newvalue'

其他回答

你可以尝试这样做:

$path = "C:\testFile.txt"
$word = "searchword"
$replacement = "ReplacementText"
$text = get-content $path 
$newText = $text -replace $word,$replacement
$newText > $path
(Get-Content file.txt) | 
Foreach-Object {$_ -replace '\[MYID\]','MyValue'}  | 
Out-File file.txt

注意(Get-Content file.txt)周围的括号是必需的:

Without the parenthesis the content is read, one line at a time, and flows down the pipeline until it reaches out-file or set-content, which tries to write to the same file, but it's already open by get-content and you get an error. The parenthesis causes the operation of content reading to be performed once (open, read and close). Only then when all lines have been read, they are piped one at a time and when they reach the last command in the pipeline they can be written to the file. It's the same as $content=content; $content | where ...

我从帕耶特的Windows Powershell in Action中找到了一个鲜为人知但非常酷的方法。您可以像引用变量一样引用文件,类似于$env:path,但需要添加花括号。

${c:file.txt} = ${c:file.txt} -replace 'oldvalue','newvalue'

我更喜欢使用。net的file类和它的静态方法,如下面的例子所示。

$content = [System.IO.File]::ReadAllText("c:\bla.txt").Replace("[MYID]","MyValue")
[System.IO.File]::WriteAllText("c:\bla.txt", $content)

这样做的优点是使用单个String,而不是像Get-Content那样使用String数组。这些方法还负责文件的编码(UTF-8 BOM等),而不需要您在大多数时候负责。

此外,与使用Get-Content和管道连接到Set-Content的算法相比,这些方法不会弄乱行结束符(可能会使用Unix行结束符)。

所以对我来说:几年下来会坏掉的东西更少。

在使用. net类时,一个鲜为人知的事情是,当您键入“[System.IO.”在PowerShell窗口中,您可以按Tab键来步进那里的方法。

这要归功于@rominator007

我把它包装成一个函数(因为你可能想再次使用它)

function Replace-AllStringsInFile($SearchString,$ReplaceString,$FullPathToFile)
{
    $content = [System.IO.File]::ReadAllText("$FullPathToFile").Replace("$SearchString","$ReplaceString")
    [System.IO.File]::WriteAllText("$FullPathToFile", $content)
}

注意:这是不区分大小写的!!!!!

请看这篇文章:字符串。替换忽略大小写