我如何排序一个数组充满了[UIFont familyNames]按字母顺序?


最简单的方法是,提供一个排序选择器(Apple的文档详细信息)

objective - c

sortedArray = [anArray sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

斯威夫特

let descriptor: NSSortDescriptor = NSSortDescriptor(key: "YourKey", ascending: true, selector: "localizedCaseInsensitiveCompare:")
let sortedResults: NSArray = temparray.sortedArrayUsingDescriptors([descriptor])

Apple为字母排序提供了几个选择器:

比较: caseInsensitiveCompare: localizedCompare: localizedCaseInsensitiveCompare: localizedStandardCompare:

斯威夫特

var students = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"]
students.sort()
print(students)
// Prints "["Abena", "Akosua", "Kofi", "Kweku", "Peter"]"

参考


这里提供的其他答案提到使用@selector(localizedCaseInsensitiveCompare:) 这对于NSString数组非常有效,但是如果你想将它扩展到另一种类型的对象,并根据'name'属性对那些对象进行排序,你应该这样做:

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES];
sortedArray=[anArray sortedArrayUsingDescriptors:@[sort]];

您的对象将根据这些对象的name属性进行排序。

如果希望排序不区分大小写,则需要像这样设置描述符

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES selector:@selector(caseInsensitiveCompare:)];

一个更强大的排序NSString列表的方法是使用NSNumericSearch:

NSArray *sortedArrayOfString = [arrayOfString sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
            return [(NSString *)obj1 compare:(NSString *)obj2 options:NSNumericSearch];
        }];

结合SortDescriptor,它会给出如下内容:

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) {
        return [(NSString *)obj1 compare:(NSString *)obj2 options:NSNumericSearch];
    }];
NSArray *sortedArray = [anArray sortedArrayUsingDescriptors:[NSArray arrayWithObject:sort]];

-(IBAction)SegmentbtnCLK:(id)sender
{ [self sortArryofDictionary];
    [self.objtable reloadData];}
-(void)sortArryofDictionary
{ NSSortDescriptor *sorter;
    switch (sortcontrol.selectedSegmentIndex)
    {case 0:
            sorter=[[NSSortDescriptor alloc]initWithKey:@"Name" ascending:YES];
            break;
        case 1:
            sorter=[[NSSortDescriptor alloc]initWithKey:@"Age" ascending:YES];
            default:
            break; }
    NSArray *sortdiscriptor=[[NSArray alloc]initWithObjects:sorter, nil];
    [arr sortUsingDescriptors:sortdiscriptor];
    }

使用以下代码按字母顺序排序:

    NSArray *unsortedStrings = @[@"Verdana", @"MS San Serif", @"Times New Roman",@"Chalkduster",@"Impact"];

    NSArray *sortedStrings =
    [unsortedStrings sortedArrayUsingSelector:@selector(compare:)];

    NSLog(@"Unsorted Array : %@",unsortedStrings);        
    NSLog(@"Sorted Array : %@",sortedStrings);

下面是控制台日志:

2015-04-02 16:17:50.614 ToDoList[2133:100512] Unsorted Array : (
    Verdana,
    "MS San Serif",
    "Times New Roman",
    Chalkduster,
    Impact
)

2015-04-02 16:17:50.615 ToDoList[2133:100512] Sorted Array : (
    Chalkduster,
    Impact,
    "MS San Serif",
    "Times New Roman",
    Verdana
)

另一个简单的方法是使用NSString description属性对字符串数组进行排序:

NSSortDescriptor *valueDescriptor = [NSSortDescriptor sortDescriptorWithKey:@"description" ascending:YES];
arrayOfSortedStrings = [arrayOfNotSortedStrings sortedArrayUsingDescriptors:@[valueDescriptor]];

对于大多数目的,这已经有了很好的答案,但我将添加我的更具体的答案。

在英语中,通常我们按字母顺序排列时,会忽略短语开头的单词“the”。所以“United States”应该在“U”下面,而不是“T”下面。

这个可以帮你。

最好把这些分类。

// Sort an array of NSStrings alphabetically, ignoring the word "the" at the beginning of a string.

-(NSArray*) sortArrayAlphabeticallyIgnoringThes:(NSArray*) unsortedArray {

    NSArray * sortedArray = [unsortedArray sortedArrayUsingComparator:^NSComparisonResult(NSString* a, NSString* b) {

        //find the strings that will actually be compared for alphabetical ordering
        NSString* firstStringToCompare = [self stringByRemovingPrecedingThe:a];
        NSString* secondStringToCompare = [self stringByRemovingPrecedingThe:b];

        return [firstStringToCompare compare:secondStringToCompare];
    }];
    return sortedArray;
}

// Remove "the"s, also removes preceding white spaces that are left as a result. Assumes no preceding whitespaces to start with. nb: Trailing white spaces will be deleted too.

-(NSString*) stringByRemovingPrecedingThe:(NSString*) originalString {
    NSString* result;
    if ([[originalString substringToIndex:3].lowercaseString isEqualToString:@"the"]) {
        result = [[originalString substringFromIndex:3] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
    }
    else {
        result = originalString;
    }
    return result;
}