我怎样才能知道我用C语言编写的应用程序打开的文件的大小? 我想知道大小,因为我想把加载文件的内容放入一个字符串,我使用malloc()分配。正在写入malloc(10000*sizeof(char));恕我直言,这是个坏主意。


当前回答

#include <stdio.h>

#define MAXNUMBER 1024

int main()
{
    int i;
    char a[MAXNUMBER];

    FILE *fp = popen("du -b  /bin/bash", "r");

    while((a[i++] = getc(fp))!= 9)
        ;

    a[i] ='\0';

    printf(" a is %s\n", a);

    pclose(fp);
    return 0;
}  

HTH

其他回答

你需要搜索到文件的末尾,然后请求位置:

fseek(fp, 0L, SEEK_END);
sz = ftell(fp);

然后你可以回头寻找,例如:

fseek(fp, 0L, SEEK_SET);

或者(如果你想从头开始)

rewind(fp);

如何使用lseek/fseek/stat/fstat获取文件大小?

#include <fcntl.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/stat.h>

void
fseek_filesize(const char *filename)
{
    FILE *fp = NULL;
    long off;

    fp = fopen(filename, "r");
    if (fp == NULL)
    {
        printf("failed to fopen %s\n", filename);
        exit(EXIT_FAILURE);
    }

    if (fseek(fp, 0, SEEK_END) == -1)
    {
        printf("failed to fseek %s\n", filename);
        exit(EXIT_FAILURE);
    }

    off = ftell(fp);
    if (off == -1)
    {
        printf("failed to ftell %s\n", filename);
        exit(EXIT_FAILURE);
    }

    printf("[*] fseek_filesize - file: %s, size: %ld\n", filename, off);

    if (fclose(fp) != 0)
    {
        printf("failed to fclose %s\n", filename);
        exit(EXIT_FAILURE);
    }
}

void
fstat_filesize(const char *filename)
{
    int fd;
    struct stat statbuf;

    fd = open(filename, O_RDONLY, S_IRUSR | S_IRGRP);
    if (fd == -1)
    {
        printf("failed to open %s\n", filename);
        exit(EXIT_FAILURE);
    }

    if (fstat(fd, &statbuf) == -1)
    {
        printf("failed to fstat %s\n", filename);
        exit(EXIT_FAILURE);
    }

    printf("[*] fstat_filesize - file: %s, size: %lld\n", filename, statbuf.st_size);

    if (close(fd) == -1)
    {
        printf("failed to fclose %s\n", filename);
        exit(EXIT_FAILURE);
    }
}

void
stat_filesize(const char *filename)
{
    struct stat statbuf;

    if (stat(filename, &statbuf) == -1)
    {
        printf("failed to stat %s\n", filename);
        exit(EXIT_FAILURE);
    }

    printf("[*] stat_filesize - file: %s, size: %lld\n", filename, statbuf.st_size);

}

void
seek_filesize(const char *filename)
{
    int fd;
    off_t off;

    if (filename == NULL)
    {
        printf("invalid filename\n");
        exit(EXIT_FAILURE);
    }

    fd = open(filename, O_RDONLY, S_IRUSR | S_IRGRP);
    if (fd == -1)
    {
        printf("failed to open %s\n", filename);
        exit(EXIT_FAILURE);
    }

    off = lseek(fd, 0, SEEK_END);
    if (off == -1)
    {
        printf("failed to lseek %s\n", filename);
        exit(EXIT_FAILURE);
    }

    printf("[*] seek_filesize - file: %s, size: %lld\n", filename, (long long) off);

    if (close(fd) == -1)
    {
        printf("failed to close %s\n", filename);
        exit(EXIT_FAILURE);
    }
}

int
main(int argc, const char *argv[])
{
    int i;

    if (argc < 2)
    {
        printf("%s <file1> <file2>...\n", argv[0]);
        exit(0);
    }

    for(i = 1; i < argc; i++)
    {
        seek_filesize(argv[i]);
        stat_filesize(argv[i]);
        fstat_filesize(argv[i]);
        fseek_filesize(argv[i]);
    }

    return 0;
}

使用标准库:

假设你的实现有意义地支持SEEK_END:

fseek(f, 0, SEEK_END); // seek to end of file
size = ftell(f); // get current file pointer
fseek(f, 0, SEEK_SET); // seek back to beginning of file
// proceed with allocating memory and reading the file

Linux / POSIX:

可以使用stat(如果知道文件名)或fstat(如果有文件描述符)。

下面是一个stat的例子:

#include <sys/stat.h>
struct stat st;
stat(filename, &st);
size = st.st_size;

Win32:

您可以使用GetFileSize或GetFileSizeEx。

如果您使用的是Linux,请认真考虑只使用glib中的g_file_get_contents函数。它处理加载文件、分配内存和处理错误的所有代码。

我最终只是做了一个简短而甜蜜的fsize函数(注意,没有错误检查)

int fsize(FILE *fp){
    int prev=ftell(fp);
    fseek(fp, 0L, SEEK_END);
    int sz=ftell(fp);
    fseek(fp,prev,SEEK_SET); //go back to where we were
    return sz;
}

标准C库没有这样的函数,这有点愚蠢,但我可以看到为什么它会很困难,因为不是每个“文件”都有大小(例如/dev/null)。