像下面这样一个简单的Enum实现怎么样?不需要外部库!

import platform
from enum import Enum
class OS(Enum):
    def checkPlatform(osName):
        return osName.lower()== platform.system().lower()

    MAC = checkPlatform("darwin")
    LINUX = checkPlatform("linux")
    WINDOWS = checkPlatform("windows")  #I haven't test this one

简单地，您可以使用Enum值访问

if OS.LINUX.value:
    print("Cool it is Linux")

附注:它是python3

一个新的答案如何:

import psutil
psutil.MACOS   #True (OSX is deprecated)
psutil.WINDOWS #False
psutil.LINUX   #False 

如果我使用MACOS，这将是输出

下面是Mac上的测试结果:

>>> import os
>>> os.name
'posix'
>>> import platform
>>> platform.system()
'Darwin'
>>> platform.release()
'8.11.1'

这个解决方案适用于python和jython。

模块os_identify.py:

import platform
import os

# This module contains functions to determine the basic type of
# OS we are running on.
# Contrary to the functions in the `os` and `platform` modules,
# these allow to identify the actual basic OS,
# no matter whether running on the `python` or `jython` interpreter.

def is_linux():
    try:
        platform.linux_distribution()
        return True
    except:
        return False

def is_windows():
    try:
        platform.win32_ver()
        return True
    except:
        return False

def is_mac():
    try:
        platform.mac_ver()
        return True
    except:
        return False

def name():
    if is_linux():
        return "Linux"
    elif is_windows():
        return "Windows"
    elif is_mac():
        return "Mac"
    else:
        return "<unknown>" 

像这样使用:

import os_identify

print "My OS: " + os_identify.name()

如果你在Windows上使用Cygwin操作系统的os.name是posix，请注意。

>>> import os, platform
>>> print os.name
posix
>>> print platform.system()
CYGWIN_NT-6.3-WOW

>>> import os
>>> os.name
'posix'
>>> import platform
>>> platform.system()
'Linux'
>>> platform.release()
'2.6.22-15-generic'

platform.system()的输出如下:

Linux: Linux 麦克:达尔文 Windows:

参见:平台-访问底层平台的识别数据