我有2个HTML文件，假设a.html和b.html。在a.html中，我想包括b.html。
在JSF中，我可以这样做:
<ui:include src="b.xhtml" />
这意味着在.xhtml文件中，我可以包含b.xhtml。
我们如何在*.html文件中做到这一点?
当前回答
PHP是一种服务器级脚本语言。它可以做很多事情，但一个流行的用途是在页面中包含HTML文档，这与SSI非常相似。与SSI一样，这是一种服务器级技术。如果你不确定你的网站上是否有PHP功能，请联系你的主机提供商。
下面是一个简单的PHP脚本，你可以使用它在任何支持PHP的网页上包含HTML片段:
将网站常用元素的HTML保存到单独的文件中。例如，导航部分可以保存为navigation.html或navigation.php。 使用下面的PHP代码将该HTML包含在每个页面中。
<?php require($DOCUMENT_ROOT . "navigation.php"); ?>
在希望包含该文件的每个页面上使用相同的代码。 确保将突出显示的文件名更改为包含文件的名称和路径。
其他回答
这对我很有帮助。为了将一个html代码块从b.html添加到a.html，这应该放在a.html的head标签中:
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
然后在body标签中，一个容器用一个唯一的id和一个javascript块来加载b.html到容器中，如下所示:
<div id="b-placeholder">
</div>
<script>
$(function(){
$("#b-placeholder").load("b.html");
});
</script>
不需要脚本。不需要做任何花哨的东西服务器端(尽管这可能是一个更好的选择)
<iframe src="/path/to/file.html" seamless></iframe>
由于旧的浏览器不支持无缝，你应该添加一些css来修复它:
iframe[seamless] {
border: none;
}
请记住，对于不支持无缝链接的浏览器，如果您单击iframe中的链接，它将使框架指向该url，而不是整个窗口。一种解决方法是让所有链接都有target="_parent"，尽管浏览器的支持是“足够好”。
html5rocks.com has a very good tutorial on this stuff, and this might be a little late, but I myself didn't know this existed. w3schools also has a way to do this using their new library called w3.js. The thing is, this requires the use of a web server and and HTTPRequest object. You can't actually load these locally and test them on your machine. What you can do though, is use polyfills provided on the html5rocks link at the top, or follow their tutorial. With a little JS magic, you can do something like this:
var link = document.createElement('link');
if('import' in link){
//Run import code
link.setAttribute('rel','import');
link.setAttribute('href',importPath);
document.getElementsByTagName('head')[0].appendChild(link);
//Create a phantom element to append the import document text to
link = document.querySelector('link[rel="import"]');
var docText = document.createElement('div');
docText.innerHTML = link.import;
element.appendChild(docText.cloneNode(true));
} else {
//Imports aren't supported, so call polyfill
importPolyfill(importPath);
}
This will make the link (Can change to be the wanted link element if already set), set the import (unless you already have it), and then append it. It will then from there take that and parse the file in HTML, and then append it to the desired element under a div. This can all be changed to fit your needs from the appending element to the link you are using. I hope this helped, it may irrelevant now if newer, faster ways have come out without using libraries and frameworks such as jQuery or W3.js.
UPDATE:这将抛出一个错误，表示本地导入已被CORS策略阻塞。可能需要访问深层网络才能使用它，因为深层网络的特性。(意思是没有实际用途)
I came to this topic looking for something similar, but a bit different from the problem posed by lolo. I wanted to construct an HTML page holding an alphabetical menu of links to other pages, and each of the other pages might or might not exist, and the order in which they were created might not be alphabetical (nor even numerical). Also, like Tafkadasoh, I did not want to bloat the web page with jQuery. After researching the problem and experimenting for several hours, here is what worked for me, with relevant remarks added:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/application/html; charset=iso-8859-1">
<meta name="Author" content="me">
<meta copyright="Copyright" content= "(C) 2013-present by me" />
<title>Menu</title>
<script type="text/javascript">
<!--
var F000, F001, F002, F003, F004, F005, F006, F007, F008, F009,
F010, F011, F012, F013, F014, F015, F016, F017, F018, F019;
var dat = new Array();
var form, script, write, str, tmp, dtno, indx, unde;
/*
The "F000" and similar variables need to exist/be-declared.
Each one will be associated with a different menu item,
so decide on how many items maximum you are likely to need,
when constructing that listing of them. Here, there are 20.
*/
function initialize()
{ window.name="Menu";
form = document.getElementById('MENU');
for(indx=0; indx<20; indx++)
{ str = "00" + indx;
tmp = str.length - 3;
str = str.substr(tmp);
script = document.createElement('script');
script.type = 'text/javascript';
script.src = str + ".js";
form.appendChild(script);
}
/*
The for() loop constructs some <script> objects
and associates each one with a different simple file name,
starting with "000.js" and, here, going up to "019.js".
It won't matter which of those files exist or not.
However, for each menu item you want to display on this
page, you will need to ensure that its .js file does exist.
The short function below (inside HTML comment-block) is,
generically, what the content of each one of the .js files looks like:
<!--
function F000()
{ return ["Menu Item Name", "./URLofFile.htm", "Description string"];
}
-->
(Continuing the remarks in the main menu.htm file)
It happens that each call of the form.appendChild() function
will cause the specified .js script-file to be loaded at that time.
However, it takes a bit of time for the JavaScript in the file
to be fully integrated into the web page, so one thing that I tried,
but it didn't work, was to write an "onload" event handler.
The handler was apparently being called before the just-loaded
JavaScript had actually become accessible.
Note that the name of the function in the .js file is the same as one
of the pre-defined variables like "F000". When I tried to access
that function without declaring the variable, attempting to use an
"onload" event handler, the JavaScript debugger claimed that the item
was "not available". This is not something that can be tested-for!
However, "undefined" IS something that CAN be tested-for. Simply
declaring them to exist automatically makes all of them "undefined".
When the system finishes integrating a just-loaded .js script file,
the appropriate variable, like "F000", will become something other
than "undefined". Thus it doesn't matter which .js files exist or
not, because we can simply test all the "F000"-type variables, and
ignore the ones that are "undefined". More on that later.
The line below specifies a delay of 2 seconds, before any attempt
is made to access the scripts that were loaded. That DOES give the
system enough time to fully integrate them into the web page.
(If you have a really long list of menu items, or expect the page
to be loaded by an old/slow computer, a longer delay may be needed.)
*/
window.setTimeout("BuildMenu();", 2000);
return;
}
//So here is the function that gets called after the 2-second delay
function BuildMenu()
{ dtno = 0; //index-counter for the "dat" array
for(indx=0; indx<20; indx++)
{ str = "00" + indx;
tmp = str.length - 3;
str = "F" + str.substr(tmp);
tmp = eval(str);
if(tmp != unde) // "unde" is deliberately undefined, for this test
dat[dtno++] = eval(str + "()");
}
/*
The loop above simply tests each one of the "F000"-type variables, to
see if it is "undefined" or not. Any actually-defined variable holds
a short function (from the ".js" script-file as previously indicated).
We call the function to get some data for one menu item, and put that
data into an array named "dat".
Below, the array is sorted alphabetically (the default), and the
"dtno" variable lets us know exactly how many menu items we will
be working with. The loop that follows creates some "<span>" tags,
and the the "innerHTML" property of each one is set to become an
"anchor" or "<a>" tag, for a link to some other web page. A description
and a "<br />" tag gets included for each link. Finally, each new
<span> object is appended to the menu-page's "form" object, and thereby
ends up being inserted into the middle of the overall text on the page.
(For finer control of where you want to put text in a page, consider
placing something like this in the web page at an appropriate place,
as preparation:
<div id="InsertHere"></div>
You could then use document.getElementById("InsertHere") to get it into
a variable, for appending of <span> elements, the way a variable named
"form" was used in this example menu page.
Note: You don't have to specify the link in the same way I did
(the type of link specified here only works if JavaScript is enabled).
You are free to use the more-standard "<a>" tag with the "href"
property defined, if you wish. But whichever way you go,
you need to make sure that any pages being linked actually exist!
*/
dat.sort();
for(indx=0; indx<dtno; indx++)
{ write = document.createElement('span');
write.innerHTML = "<a onclick=\"window.open('" + dat[indx][1] +
"', 'Menu');\" style=\"color:#0000ff;" +
"text-decoration:underline;cursor:pointer;\">" +
dat[indx][0] + "</a> " + dat[indx][2] + "<br />";
form.appendChild(write);
}
return;
}
// -->
</script>
</head>
<body onload="initialize();" style="background-color:#a0a0a0; color:#000000;
font-family:sans-serif; font-size:11pt;">
<h2>
MENU
<noscript><br /><span style="color:#ff0000;">
Links here only work if<br />
your browser's JavaScript<br />
support is enabled.</span><br /></noscript></h2>
These are the menu items you currently have available:<br />
<br />
<form id="MENU" action="" onsubmit="return false;">
<!-- Yes, the <form> object starts out completely empty -->
</form>
Click any link, and enjoy it as much as you like.<br />
Then use your browser's BACK button to return to this Menu,<br />
so you can click a different link for a different thing.<br />
<br />
<br />
<small>This file (web page) Copyright (c) 2013-present by me</small>
</body>
</html>
这里有几种类型的答案，但我从来没有发现这里使用的最古老的工具:
“其他的答案对我都不管用。”
<html>
<head>
<title>pagetitle</title>
</head>
<frameset rows="*" framespacing="0" border="0" frameborder="no" frameborder="0">
<frame name="includeName" src="yourfileinclude.html" marginwidth="0" marginheight="0" scrolling="no" frameborder="0">
</frameset>
</html>
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