只是想提到一种情况，在这种情况下使用OBJECT_ID方法可能会更容易一些。INFORMATION_SCHEMA视图是每个数据库-下的对象

信息模式视图定义在一个名为 INFORMATION_SCHEMA。这个模式包含在每个数据库中。

https://msdn.microsoft.com/en-us/library/ms186778.aspx

因此，您访问的所有表都使用

IF EXISTS (SELECT 1 
           FROM [database].INFORMATION_SCHEMA.TABLES 
           WHERE TABLE_TYPE='BASE TABLE' 
           AND TABLE_NAME='mytablename') 
   SELECT 1 AS res ELSE SELECT 0 AS res;

将只反映什么是在[数据库]。如果您想检查另一个数据库中是否存在表，而不需要每次都动态更改[database]， OBJECT_ID将允许您开箱操作。除

IF OBJECT_ID (N'db1.schema.table1', N'U') IS NOT NULL 
   SELECT 1 AS res ELSE SELECT 0 AS res;

效果和

IF OBJECT_ID (N'db2.schema.table1', N'U') IS NOT NULL 
   SELECT 1 AS res ELSE SELECT 0 AS res;

SQL SERVER 2016编辑:

从2016年开始，微软通过添加if exists关键字来删除语句，简化了在删除之前检查不存在对象的功能。例如,

drop table if exists mytablename

将在一行代码中完成与OBJECT_ID / INFORMATION_SCHEMA包装器相同的事情。

https://blogs.msdn.microsoft.com/sqlserverstorageengine/2015/11/03/drop-if-exists-new-thing-in-sql-server-2016/

如果你需要使用不同的数据库:

DECLARE @Catalog VARCHAR(255)
SET @Catalog = 'MyDatabase'

DECLARE @Schema VARCHAR(255)
SET @Schema = 'dbo'

DECLARE @Table VARCHAR(255)
SET @Table = 'MyTable'

IF (EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES   
    WHERE TABLE_CATALOG = @Catalog 
      AND TABLE_SCHEMA = @Schema 
      AND TABLE_NAME = @Table))
BEGIN
   --do stuff
END

对于那些还没有找到解决方案的人来说，有一些重要的事情需要知道: SQL server = MYSQL。 如果你想用MYSQL来做，这很简单

    $sql = "SELECT 1 FROM `db_name`.`table_name` LIMIT 1;";
    $result = mysql_query($sql);
    if( $result == false )
        echo "table DOES NOT EXIST";
    else
        echo "table exists";

把这个贴在这里，因为它是谷歌的热门。

-- -- create过程检查表是否存在

DELIMITER $$

DROP PROCEDURE IF EXISTS `checkIfTableExists`;

CREATE PROCEDURE checkIfTableExists(
    IN databaseName CHAR(255),
    IN tableName CHAR(255),
    OUT boolExistsOrNot CHAR(40)
)

  BEGIN
      SELECT count(*) INTO boolExistsOrNot FROM information_schema.TABLES
      WHERE (TABLE_SCHEMA = databaseName)
      AND (TABLE_NAME = tableName);
  END $$

DELIMITER ;

-- --如何使用:检查表迁移是否存在

 CALL checkIfTableExists('muDbName', 'migrations', @output);

为了开发人员和其他dba的利益，这里只是添加了一些内容

接收@Tablename作为参数的脚本

(可能包含也可能不包含模式名)并返回下面的信息。表存在:

the_name                object_id   the_schema  the_table       the_type
[Facts].[FactBackOrder] 758293761   Facts       FactBackOrder   Table

我制作了这个脚本，以便在每次需要测试表或视图是否存在时在其他脚本中使用，当它存在时，获取它的object_id用于其他目的。

当您传递了空字符串、错误的模式名或错误的表名时，将引发错误。

例如，它可以在过程中返回-1。

例如，我有一个名为“事实”的表格。在我的数据仓库数据库之一的FactBackOrder。

我是这样做到的:

PRINT 'THE SERVER IS ' + @@SERVERNAME
--select db_name()
PRINT 'THE DATABASE IS ' + db_NAME() 
PRINT ''
GO

SET NOCOUNT ON
GO

--===================================================================================
-- @TableName is the parameter
-- the object we want to deal with (it might be an indexed view or a table)
-- the schema might or might not be specified
-- when not specified it is DBO
--===================================================================================

DECLARE @TableName SYSNAME

SELECT @TableName = 'Facts.FactBackOrder'
--===================================================================================
--===================================================================================
DECLARE @Schema SYSNAME
DECLARE @I INT
DECLARE @Z INT 

SELECT @TableName = LTRIM(RTRIM(@TableName))
SELECT @Z = LEN(@TableName)

IF (@Z = 0) BEGIN

            RAISERROR('Invalid @Tablename passed.',16,1)

END 

SELECT @I = CHARINDEX('.',@TableName )
--SELECT @TableName ,@I

IF @I > 0 BEGIN

        --===================================================================================
        -- a schema and table name have been passed
        -- example Facts.FactBackOrder 
        -- @Schema = Fact
        -- @TableName = FactBackOrder
        --===================================================================================

   SELECT @Schema    = SUBSTRING(@TABLENAME,1,@I-1)
   SELECT @TableName = SUBSTRING(@TABLENAME,@I+1,@Z-@I)



END
ELSE BEGIN

        --===================================================================================
        -- just a table name have been passed
        -- so the schema will be dbo
        -- example Orders
        -- @Schema = dbo
        -- @TableName = Orders
        --===================================================================================

   SELECT @Schema    = 'DBO'     


END

        --===================================================================================
        -- Check whether the @SchemaName is valid in the current database
        --===================================================================================

IF NOT EXISTS ( SELECT * FROM INFORMATION_SCHEMA.SCHEMATA K WHERE K.[SCHEMA_NAME] = @Schema ) BEGIN

            RAISERROR('Invalid Schema Name.',16,1)

END 

--SELECT @Schema  as [@Schema]
--      ,@TableName as [@TableName]


DECLARE @R1 TABLE (

   THE_NAME SYSNAME
  ,THE_SCHEMA SYSNAME
  ,THE_TABLE SYSNAME
  ,OBJECT_ID INT
  ,THE_TYPE SYSNAME
  ,PRIMARY KEY CLUSTERED (THE_SCHEMA,THE_NAME)

)

;WITH RADHE_01 AS (
SELECT QUOTENAME(SCHEMA_NAME(O.schema_id)) + '.' + QUOTENAME(O.NAME) AS [the_name]
      ,the_schema=SCHEMA_NAME(O.schema_id)
      ,the_table=O.NAME
      ,object_id =o.object_id 
      ,[the_type]= CASE WHEN O.TYPE = 'U' THEN 'Table' ELSE 'View' END 
from sys.objects O
where O.is_ms_shipped = 0
AND O.TYPE IN ('U','V')
)
INSERT INTO @R1 (
   THE_NAME 
  ,THE_SCHEMA 
  ,THE_TABLE 
  ,OBJECT_ID
  ,THE_TYPE 
)
SELECT  the_name
       ,the_schema
       ,the_table
       ,object_id
       ,the_type
FROM RADHE_01
WHERE the_schema = @Schema 
  AND the_table  = @TableName

IF (@@ROWCOUNT = 0) BEGIN 

             RAISERROR('Invalid Table Name.',16,1)

END 
ELSE BEGIN

    SELECT     THE_NAME 
              ,THE_SCHEMA 
              ,THE_TABLE 
              ,OBJECT_ID
              ,THE_TYPE 

    FROM @R1

END 

你可以用这个:

     IF OBJECT_ID (N'dbo.T', N'U') IS NOT NULL 
        BEGIN 
            print 'deleted table';
            drop table t 
        END
     else 
        begin 
            print 'table not found' 
        end

 Create table t (id int identity(1,1) not null, name varchar(30) not null, lastname varchar(25) null)
 insert into t( name, lastname) values('john','doe');
 insert into t( name, lastname) values('rose',NULL);

 Select * from t
1   john    doe
2   rose    NULL

 -- clean
 drop table t