使用尝试除外,并从 errno 模块的正确错误代码可以摆脱赛车状态,并是跨平台:

import os
import errno

def make_sure_path_exists(path):
    try:
        os.makedirs(path)
    except OSError as exception:
        if exception.errno != errno.EEXIST:
            raise

换句话说,我们试图创建目录,但如果它们已经存在,我们会忽略错误。 另一方面,任何其他错误都会被报告. 例如,如果您提前创建 dir 'a' 并从中删除所有权限,您将获得一个 OSError 提取的 errno.EACCES (Permission denied, error 13)。

试试 os.path.exist 函数

if not os.path.exists(dir):
    os.mkdir(dir)

我找到了这个Q/A之后我被一些失败和错误我得到,当我在Python的目录工作,我在Python 3工作(在一个Anaconda虚拟环境中的3.5在一个Arch Linux x86_64系统)。

考虑此目录结构:

└── output/         ## dir
   ├── corpus       ## file
   ├── corpus2/     ## dir
   └── subdir/      ## dir

下面是我的实验 / 笔记,提供澄清:

# ----------------------------------------------------------------------------
# [1] https://stackoverflow.com/questions/273192/how-can-i-create-a-directory-if-it-does-not-exist

import pathlib

""" Notes:
        1.  Include a trailing slash at the end of the directory path
            ("Method 1," below).
        2.  If a subdirectory in your intended path matches an existing file
            with same name, you will get the following error:
            "NotADirectoryError: [Errno 20] Not a directory:" ...
"""
# Uncomment and try each of these "out_dir" paths, singly:

# ----------------------------------------------------------------------------
# METHOD 1:
# Re-running does not overwrite existing directories and files; no errors.

# out_dir = 'output/corpus3'                ## no error but no dir created (missing tailing /)
# out_dir = 'output/corpus3/'               ## works
# out_dir = 'output/corpus3/doc1'           ## no error but no dir created (missing tailing /)
# out_dir = 'output/corpus3/doc1/'          ## works
# out_dir = 'output/corpus3/doc1/doc.txt'   ## no error but no file created (os.makedirs creates dir, not files!  ;-)
# out_dir = 'output/corpus2/tfidf/'         ## fails with "Errno 20" (existing file named "corpus2")
# out_dir = 'output/corpus3/tfidf/'         ## works
# out_dir = 'output/corpus3/a/b/c/d/'       ## works

# [2] https://docs.python.org/3/library/os.html#os.makedirs

# Uncomment these to run "Method 1":

#directory = os.path.dirname(out_dir)
#os.makedirs(directory, mode=0o777, exist_ok=True)

# ----------------------------------------------------------------------------
# METHOD 2:
# Re-running does not overwrite existing directories and files; no errors.

# out_dir = 'output/corpus3'                ## works
# out_dir = 'output/corpus3/'               ## works
# out_dir = 'output/corpus3/doc1'           ## works
# out_dir = 'output/corpus3/doc1/'          ## works
# out_dir = 'output/corpus3/doc1/doc.txt'   ## no error but creates a .../doc.txt./ dir
# out_dir = 'output/corpus2/tfidf/'         ## fails with "Errno 20" (existing file named "corpus2")
# out_dir = 'output/corpus3/tfidf/'         ## works
# out_dir = 'output/corpus3/a/b/c/d/'       ## works

# Uncomment these to run "Method 2":

#import os, errno
#try:
#       os.makedirs(out_dir)
#except OSError as e:
#       if e.errno != errno.EEXIST:
#               raise
# ----------------------------------------------------------------------------

结论:我认为“方法2”更强大。

[1] 我如何安全地创建一张被锁定的目录?

[2] https://docs.python.org/3/图书馆/os.html#os.makedirs

在创建目录之前,您必须设置完整的路径:

import os,sys,inspect
import pathlib

currentdir = os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))
your_folder = currentdir + "/" + "your_folder"

if not os.path.exists(your_folder):
   pathlib.Path(your_folder).mkdir(parents=True, exist_ok=True)

这对我工作,我希望这对你也工作。

最快的安全方式是:如果不存在,它会创造,如果不存在,它会消失:

from pathlib import Path
Path("path/with/childs/.../").mkdir(parents=True, exist_ok=True)

在您的程序/项目的输入点上拨打 Create_dir() 函数。

import os

def create_dir(directory):
    if not os.path.exists(directory):
        print('Creating Directory '+directory)
        os.makedirs(directory)

create_dir('Project directory')