根据上面的答案和其他类似的关于CLI进度条的问题，我想我得到了一个普遍的答案。请登录https://stackoverflow.com/a/15860757/2254146查看。

下面是这个函数的一个副本，但是为了适合你的风格进行了修改:

import time, sys

# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
    barLength = 20 # Modify this to change the length of the progress bar
    status = ""
    if isinstance(progress, int):
        progress = float(progress)
    if not isinstance(progress, float):
        progress = 0
        status = "error: progress var must be float\r\n"
    if progress < 0:
        progress = 0
        status = "Halt...\r\n"
    if progress >= 1:
        progress = 1
        status = "Done...\r\n"
    block = int(round(barLength*progress))
    text = "\rPercent: [{0}] {1}% {2}".format( "="*block + " "*(barLength-block), progress*100, status)
    sys.stdout.write(text)
    sys.stdout.flush()

看起来像

百分比:[====================]99.0%

你可以使用\r(回车)。演示:

import sys
total = 10000000
point = total / 100
increment = total / 20
for i in xrange(total):
    if(i % (5 * point) == 0):
        sys.stdout.write("\r[" + "=" * (i / increment) +  " " * ((total - i)/ increment) + "]" +  str(i / point) + "%")
        sys.stdout.flush()

正如Mark Rushakoff的解决方案中所描述的，您可以输出回车符sys.stdout.write('\r')来将光标重置到行首。要泛化该解决方案，同时实现Python 3的f- string，您可以使用

from time import sleep
import sys

n_bar = 50
iterable = range(33)  # for demo purposes
n_iter = len(iterable)
for i, item in enumerate(iterable):
    j = (i + 1) / n_iter

    sys.stdout.write('\r')
    sys.stdout.write(f"[{'=' * int(n_bar * j):{n_bar}s}] {int(100 * j)}%")
    sys.stdout.flush()

    sleep(0.05)  
    # do something with <item> here

'\r'字符(回车)将光标重置到行首，并允许您重写该行之前的内容。

from time import sleep
import sys

for i in range(21):
    sys.stdout.write('\r')
    # the exact output you're looking for:
    sys.stdout.write("[%-20s] %d%%" % ('='*i, 5*i))
    sys.stdout.flush()
    sleep(0.25)

我不能100%确定这是否可以在所有系统上完全移植，但它至少可以在Linux和OSX上运行。

在这里你可以使用以下代码作为函数:

def drawProgressBar(percent, barLen = 20):
    sys.stdout.write("\r")
    progress = ""
    for i in range(barLen):
        if i < int(barLen * percent):
            progress += "="
        else:
            progress += " "
    sys.stdout.write("[ %s ] %.2f%%" % (progress, percent * 100))
    sys.stdout.flush()

使用.format:

def drawProgressBar(percent, barLen = 20):
    # percent float from 0 to 1. 
    sys.stdout.write("\r")
    sys.stdout.write("[{:<{}}] {:.0f}%".format("=" * int(barLen * percent), barLen, percent * 100))
    sys.stdout.flush()

要成为纯python并且不进行系统调用:

from time import sleep

for i in range(21):
    spaces = " " * (20 - i)
    percentage = 5*i
    print(f"\r[{'='*i}{spaces}]{percentage}%", flush=True, end="")
    sleep(0.25)