我如何将一个NSString像“01/02/10”(意思是2010年2月1日)转换成一个NSDate?如何将NSDate转换回字符串?


当前回答

为什么不给NSString添加一个category ?

// NSString+Date.h
@interface NSString (Date)
+ (NSDate*)stringDateFromString:(NSString*)string;
+ (NSString*)stringDateFromDate:(NSDate*)date;
@end


// NSString+Date.m
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init];
[dateFormatter setDateFormat:@"EEE, dd MMM yyyy HH:mm:ss ZZZ"];

NSDate *date = [dateFormatter dateFromString:stringDate ];
[dateFormatter release];
+ (NSDateFormatter*)stringDateFormatter
{
    static NSDateFormatter* formatter = nil;
    if (formatter == nil)
    {
        formatter = [[NSDateFormatter alloc] init];
        [formatter setDateFormat:@"EEE, dd MMM yyyy HH:mm:ss ZZZ"];
    }   
    return formatter;
}

+ (NSDate*)stringDateFromString:(NSString*)string
{
    return [[NSString stringDateFormatter] dateFromString:string];
}

+ (NSString*)stringDateFromDate:(NSDate*)date
{
    return [[NSString stringDateFormatter] stringFromDate:date];
}


// Usage (#import "NSString+Date.h") or add in "YOUR PROJECT".pch file
NSString* string = [NSString stringDateFromDate:[NSDate date]];
NSDate* date = [NSString stringDateFromString:string];

其他回答

您可以为此使用扩展。

extension NSDate {
    //NSString to NSDate
    convenience
    init(dateString:String) {
        let nsDateFormatter = NSDateFormatter()
        nsDateFormatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
        // Add the locale if required here
        let dateObj = nsDateFormatter.dateFromString(dateString)
        self.init(timeInterval:0, sinceDate:dateObj!)
    }

    //NSDate to time string
    func getTime() -> String {
        let timeFormatter = NSDateFormatter()
        timeFormatter.dateFormat = "hh:mm"
        //Can also set the default styles for date or time using .timeStyle or .dateStyle
        return timeFormatter.stringFromDate(self)
    }

    //NSDate to date string
    func getDate() -> String {
        let dateFormatter = NSDateFormatter()
        dateFormatter.dateFormat = "dd, MMM"
        return dateFormatter.stringFromDate(self)
    }

    //NSDate to String
    func getString() -> String {
        let dateFormatter = NSDateFormatter()
        dateFormatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
        return dateFormatter.stringFromDate(self)
    }
}

因此,在执行时,实际代码将如下所示

    var dateObjFromString = NSDate(dateString: cutDateTime)
    var dateString = dateObjFromString.getDate()
    var timeString = dateObjFromString.getTime()
    var stringFromDate = dateObjFromString.getString()

也有一些默认方法,但我猜它可能不适用于您从文档中给出的格式

    -dateFromString(_:)
    -stringFromDate(_:)
    -localizedStringFromDate(_ date: NSDate,
                     dateStyle dateStyle: NSDateFormatterStyle,
                     timeStyle timeStyle: NSDateFormatterStyle) -> String

上面的例子不是简单地为Swift 3.0+编写的

更新- Swift 3.0+ -转换日期到字符串

let date = Date() // insert your date data here
var dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd" // add custom format if you'd like 
var dateString = dateFormatter.string(from: date)

为什么不给NSString添加一个category ?

// NSString+Date.h
@interface NSString (Date)
+ (NSDate*)stringDateFromString:(NSString*)string;
+ (NSString*)stringDateFromDate:(NSDate*)date;
@end


// NSString+Date.m
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init];
[dateFormatter setDateFormat:@"EEE, dd MMM yyyy HH:mm:ss ZZZ"];

NSDate *date = [dateFormatter dateFromString:stringDate ];
[dateFormatter release];
+ (NSDateFormatter*)stringDateFormatter
{
    static NSDateFormatter* formatter = nil;
    if (formatter == nil)
    {
        formatter = [[NSDateFormatter alloc] init];
        [formatter setDateFormat:@"EEE, dd MMM yyyy HH:mm:ss ZZZ"];
    }   
    return formatter;
}

+ (NSDate*)stringDateFromString:(NSString*)string
{
    return [[NSString stringDateFormatter] dateFromString:string];
}

+ (NSString*)stringDateFromDate:(NSDate*)date
{
    return [[NSString stringDateFormatter] stringFromDate:date];
}


// Usage (#import "NSString+Date.h") or add in "YOUR PROJECT".pch file
NSString* string = [NSString stringDateFromDate:[NSDate date]];
NSDate* date = [NSString stringDateFromString:string];

如果现在有人有兴趣在Swift中做这样的事情,我已经开始做了一些事情,尽管它并不完美。

func detectDate(dateString: NSString) -> NSDate {

    var error: NSError?
    let detector: NSDataDetector = NSDataDetector.dataDetectorWithTypes(NSTextCheckingType.Date.toRaw(), error: &error)!

    if error == nil {
        var matches = detector.matchesInString(dateString, options: nil, range: NSMakeRange(0, dateString.length))

        let currentLocale = NSLocale.currentLocale()
        for match in matches {
            match.resultType == NSTextCheckingType.Date
            NSLog("Date: \(match.date.description)")
            return match.date
        }
    }
    return NSDate()
}

用“10”来表示年份是不好的,因为它可以是1910年、1810年等。你可能应该用4位数来表示。

如果你能把日期改成

yyyymmdd

然后你可以使用:

// Convert string to date object
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyyMMdd"];
NSDate *date = [dateFormat dateFromString:dateStr];  

// Convert date object to desired output format
[dateFormat setDateFormat:@"EEEE MMMM d, YYYY"];
dateStr = [dateFormat stringFromDate:date];  
[dateFormat release];