我得到以下错误:

***************************
APPLICATION FAILED TO START
***************************

Description:

Parameter 0 of method setApplicant in webService.controller.RequestController required a bean of type 'com.service.applicant.Applicant' that could not be found.


Action:

Consider defining a bean of type 'com.service.applicant.Applicant' in your configuration.

我以前从未见过这个错误,但奇怪的是@Autowire不工作。项目结构如下:

申请人接口

public interface Applicant {

    TApplicant findBySSN(String ssn) throws ServletException;

    void deleteByssn(String ssn) throws ServletException;

    void createApplicant(TApplicant tApplicant) throws ServletException;

    void updateApplicant(TApplicant tApplicant) throws ServletException;

    List<TApplicant> getAllApplicants() throws ServletException;
}

ApplicantImpl

@Service
@Transactional
public class ApplicantImpl implements Applicant {

private static Log log = LogFactory.getLog(ApplicantImpl.class);

    private TApplicantRepository applicantRepo;

@Override
    public List<TApplicant> getAllApplicants() throws ServletException {

        List<TApplicant> applicantList = applicantRepo.findAll();

        return applicantList;
    }
}

现在我应该能够自动连线申请人,并能够访问,但在这种情况下,当我在@RestController中调用它时,它是不工作的:

@RestController
public class RequestController extends LoggingAware {

    private Applicant applicant;

    @Autowired
    public void setApplicant(Applicant applicant){
        this.applicant = applicant;
    }

    @RequestMapping(value="/", method = RequestMethod.GET)
    public String helloWorld() {

        try {
            List<TApplicant> applicantList = applicant.getAllApplicants();

            for (TApplicant tApplicant : applicantList){
                System.out.println("Name: "+tApplicant.getIndivName()+" SSN "+tApplicant.getIndSsn());
            }

            return "home";
        }
        catch (ServletException e) {
            e.printStackTrace();
        }

        return "error";
    }

}

------------------------ 更新1 -----------------------

我添加了

@SpringBootApplication
@ComponentScan("module-service")
public class WebServiceApplication extends SpringBootServletInitializer {

    @Override protected SpringApplicationBuilder configure(SpringApplicationBuilder builder) {
        return builder.sources(WebServiceApplication.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(WebServiceApplication.class, args);
    }

}

错误消失了,但什么也没发生。然而,当我在添加@ComponentScan()之前注释掉所有与RestController中的申请人相关的内容时,我能够返回一个字符串的UI,从而意味着我的RestController正在工作,现在它被跳过了。我丑陋的白色标签错误页现在。

--------------------- 更新2 ------------------------------

我添加了它所抱怨的bean的基本包。错误读取:

***************************
APPLICATION FAILED TO START
***************************

Description:

Parameter 0 of method setApplicantRepo in com.service.applicant.ApplicantImpl required a bean of type 'com.delivery.service.request.repository.TApplicantRepository' that could not be found.


Action:

Consider defining a bean of type 'com.delivery.request.request.repository.TApplicantRepository' in your configuration.

我添加了@ComponentScan

@SpringBootApplication
@ComponentScan({"com.delivery.service","com.delivery.request"})
public class WebServiceApplication extends SpringBootServletInitializer {

    @Override protected SpringApplicationBuilder configure(SpringApplicationBuilder builder) {
        return builder.sources(WebServiceApplication.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(WebServiceApplication.class, args);
    }

}

---------------------------- 更新3 ----------------------

添加:

@SpringBootApplication
@ComponentScan("com")
public class WebServiceApplication extends SpringBootServletInitializer {

仍然在抱怨我的ApplicantImpl类@自动连接我的repo TApplicantRepository到它。


当前回答

如果你使用接口,你可以扩展CrudRepository<申请人,长> @Repository注释。

其他回答

我认为你可以通过使用@Repository注释你的存储库来简化它,然后Spring框架就会自动启用它。

如果@Service类被标记为抽象,就会发生这种情况。

在应用程序中添加以下注释后,它为我工作:

@ComponentScan ({com.seic.deliveryautomation.mapper "})

我得到以下错误:

"构造函数中的参数1需要一个类型映射器的bean,但找不到:

@SpringBootApplication
@MapperScan("com.developer.project.mapper")

public class Application {
    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

我在Spring Boot 2的Maven多模块项目中遇到了熟悉的问题。这个问题与子Maven模块中包的命名有关。

@SpringBootApplication封装了很多组件,比如@ComponentScan, @EnableAutoConfiguration, jpa-repositories, json-serialization等等。他把@ComponentScan放在了com.*******中。空间方案。这部分的包com.*******。所有模块的空间必须是公用的。

解决方法:

您应该重命名所有模块包。换句话说,您必须在所有Maven模块的所有包中都有相同的父部分。例如- com.*******.space 此外,您必须将您的入口点移动到这个包- com.*******.space