Java:

public static boolean isValidEmail(CharSequence target) {
    return (!TextUtils.isEmpty(target) && Patterns.EMAIL_ADDRESS.matcher(target).matches());
}

科特林：

fun CharSequence?.isValidEmail() = !isNullOrEmpty() && Patterns.EMAIL_ADDRESS.matcher(this).matches()

编辑:它将在Android 2.2+以上工作!!

编辑:添加缺失;

试试这个

public static final Pattern EMAIL_ADDRESS_PATTERN = Pattern.compile(

              "[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" +
              "\\@" +
              "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" +
              "(" +
              "\\." +
              "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" +
              ")+"
          );

并在编辑文本

final String emailText = email.getText().toString();
EMAIL_ADDRESS_PATTERN.matcher(emailText).matches()

public static boolean isEmailValid(String email) {
    boolean isValid = false;

    String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
    CharSequence inputStr = email;

    Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(inputStr);
    if (matcher.matches()) {
        isValid = true;
    }
    return isValid;
}

我是这样做的:

增加检查邮箱地址是否有效的方法:

private boolean isValidEmailId(String email){

    return Pattern.compile("^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@"
              + "((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
              + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\."
              + "([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
              + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
              + "([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$").matcher(email).matches();
     }

现在用String of EditText检查:

if(isValidEmailId(edtEmailId.getText().toString().trim())){
  Toast.makeText(getApplicationContext(), "Valid Email Address.", Toast.LENGTH_SHORT).show();
}else{       
  Toast.makeText(getApplicationContext(), "InValid Email Address.", Toast.LENGTH_SHORT).show();
}

Done

Java:

public static boolean isValidEmail(CharSequence target) {
    return (!TextUtils.isEmpty(target) && Patterns.EMAIL_ADDRESS.matcher(target).matches());
}

科特林：

fun CharSequence?.isValidEmail() = !isNullOrEmpty() && Patterns.EMAIL_ADDRESS.matcher(this).matches()

编辑:它将在Android 2.2+以上工作!!

编辑:添加缺失;

这是我创建的一个示例方法来验证电子邮件地址，如果传递的字符串参数是一个有效的电子邮件地址，它返回true，否则返回false。

private boolean validateEmailAddress(String emailAddress){
    String  expression="^[\\w\\-]([\\.\\w])+[\\w]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";  
       CharSequence inputStr = emailAddress;  
       Pattern pattern = Pattern.compile(expression,Pattern.CASE_INSENSITIVE);  
       Matcher matcher = pattern.matcher(inputStr);  
       return matcher.matches();
}