在Node.js v4中，你可以使用ES6的Template字符串

var my_name = 'John';
var s = `hello ${my_name}, how are you doing`;
console.log(s); // prints hello John, how are you doing

你需要在'(反撇号)而不是'(撇号)内换行字符串

如果你使用的是ES6，你应该使用模板文字。

//you can do this
let sentence = `My name is ${ user.name }. Nice to meet you.`

点击此处阅读更多信息: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Template_literals

如果使用node.js, console.log()将format string作为第一个参数:

 console.log('count: %d', count);

这样做:

s = 'hello ' + my_name + ', how are you doing'

更新

使用ES6，你也可以这样做:

s = `hello ${my_name}, how are you doing`

var user = "your name";
var s = 'hello ' + user + ', how are you doing';

我写了一个函数来精确地解决这个问题。

第一个参数是要参数化的字符串。你应该把你的变量放在这个字符串中，就像这样“%s1， %s2，…”% s12”。

其他参数分别是该字符串的参数。

/***
 * @example parameterizedString("my name is %s1 and surname is %s2", "John", "Doe");
 * @return "my name is John and surname is Doe"
 *
 * @firstArgument {String} like "my name is %s1 and surname is %s2"
 * @otherArguments {String | Number}
 * @returns {String}
 */
const parameterizedString = (...args) => {
  const str = args[0];
  const params = args.filter((arg, index) => index !== 0);
  if (!str) return "";
  return str.replace(/%s[0-9]+/g, matchedStr => {
    const variableIndex = matchedStr.replace("%s", "") - 1;
    return params[variableIndex];
  });
}

例子

parameterizedString("my name is %s1 and surname is %s2", "John", "Doe");
// returns "my name is John and surname is Doe"

parameterizedString("this%s1 %s2 %s3", " method", "sooo", "goood");
// returns "this method sooo goood"

如果变量位置在字符串中改变了，这个函数也支持它而不改变函数参数。

parameterizedString("i have %s2 %s1 and %s4 %s3.", "books", 5, "pencils", "6");
// returns "i have 5 books and 6 pencils."