如何记录Python异常?
try:
do_something()
except:
# How can I log my exception here, complete with its traceback?
如何记录Python异常?
try:
do_something()
except:
# How can I log my exception here, complete with its traceback?
当前回答
您可以使用记录器在任何级别(DEBUG, INFO,…)获得跟踪。注意使用日志记录。异常时,级别为ERROR。
# test_app.py
import sys
import logging
logging.basicConfig(level="DEBUG")
def do_something():
raise ValueError(":(")
try:
do_something()
except Exception:
logging.debug("Something went wrong", exc_info=sys.exc_info())
DEBUG:root:Something went wrong
Traceback (most recent call last):
File "test_app.py", line 10, in <module>
do_something()
File "test_app.py", line 7, in do_something
raise ValueError(":(")
ValueError: :(
编辑:
这也可以(使用python 3.6)
logging.debug("Something went wrong", exc_info=True)
其他回答
使用exc_info选项可能更好,保留警告或错误标题:
try:
# coode in here
except Exception as e:
logging.error(e, exc_info=True)
使用日志记录。Exception:处理程序/块中的异常,以记录当前异常和跟踪信息,并添加一条消息。
import logging
LOG_FILENAME = '/tmp/logging_example.out'
logging.basicConfig(filename=LOG_FILENAME, level=logging.DEBUG)
logging.debug('This message should go to the log file')
try:
run_my_stuff()
except:
logging.exception('Got exception on main handler')
raise
现在查看日志文件/tmp/logging_example.out:
DEBUG:root:This message should go to the log file
ERROR:root:Got exception on main handler
Traceback (most recent call last):
File "/tmp/teste.py", line 9, in <module>
run_my_stuff()
NameError: name 'run_my_stuff' is not defined
您可以使用记录器在任何级别(DEBUG, INFO,…)获得跟踪。注意使用日志记录。异常时,级别为ERROR。
# test_app.py
import sys
import logging
logging.basicConfig(level="DEBUG")
def do_something():
raise ValueError(":(")
try:
do_something()
except Exception:
logging.debug("Something went wrong", exc_info=sys.exc_info())
DEBUG:root:Something went wrong
Traceback (most recent call last):
File "test_app.py", line 10, in <module>
do_something()
File "test_app.py", line 7, in do_something
raise ValueError(":(")
ValueError: :(
编辑:
这也可以(使用python 3.6)
logging.debug("Something went wrong", exc_info=True)
我就是这么做的。
try:
do_something()
except:
# How can I log my exception here, complete with its traceback?
import traceback
traceback.format_exc() # this will print a complete trace to stout.
下面是一个使用sys.excepthook的版本
import traceback
import sys
logger = logging.getLogger()
def handle_excepthook(type, message, stack):
logger.error(f'An unhandled exception occured: {message}. Traceback: {traceback.format_tb(stack)}')
sys.excepthook = handle_excepthook