在SQL Server中…

SELECT [name] AS [Column Name]
FROM syscolumns
WHERE id = (SELECT id FROM sysobjects WHERE type = 'V' AND [Name] = 'Your table name')

Type = 'V'表示视图 Type = 'U'表示表

试试这个

select * from sys.all_columns c join sys.objects o on c.object_id=o.object_id where o.name = 'TABLENAME' and c.name like '%COLUMN NAME%'

Mysql

SHOW COLUMNS FROM a_table_named_users WHERE Field REGEXP 'user_id|user_name|user_pass'

这将返回一个类似这样的结果:

Field     |  Type        |   Null   |   Key   |   Default   |   Extra  
user_id      int(8)          NO         PRI       NULL          auto_increment
user_name    varchar(64)     NO         MUL       NULL
user_pass    varchar(64)     NO                   NULL

然后你可以简单地提取出这些值

fetch row[0]

这对于动态传递输入也很好，因为REGEXP需要'|'来进行多个输入，但这也是一种保持数据分离并易于存储/传递给类/函数的方法。

为了安全起见，也可以尝试在发送数据时加入虚拟数据，并比较接收错误时返回的数据。

您可以运行此查询

SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%%' --if you want to find specific column write here 
ORDER BY schema_name, table_name;

在SQL Server中…

SELECT [name] AS [Column Name]
FROM syscolumns
WHERE id = (SELECT id FROM sysobjects WHERE type = 'V' AND [Name] = 'Your table name')

Type = 'V'表示视图 Type = 'U'表示表

我是这样做的

SELECT 
    TOP 0
    *
FROM
    Posts

它甚至可以在http://data.stackexchange.com的服务表我不知道!