在类文件中添加以下代码：

final TelephonyManager tm = (TelephonyManager) getBaseContext()
            .getSystemService(SplashActivity.TELEPHONY_SERVICE);
    final String tmDevice, tmSerial, androidId;
    tmDevice = "" + tm.getDeviceId();
    Log.v("DeviceIMEI", "" + tmDevice);
    tmSerial = "" + tm.getSimSerialNumber();
    Log.v("GSM devices Serial Number[simcard] ", "" + tmSerial);
    androidId = "" + android.provider.Settings.Secure.getString(getContentResolver(),
            android.provider.Settings.Secure.ANDROID_ID);
    Log.v("androidId CDMA devices", "" + androidId);
    UUID deviceUuid = new UUID(androidId.hashCode(),
            ((long) tmDevice.hashCode() << 32) | tmSerial.hashCode());
    String deviceId = deviceUuid.toString();
    Log.v("deviceIdUUID universally unique identifier", "" + deviceId);
    String deviceModelName = android.os.Build.MODEL;
    Log.v("Model Name", "" + deviceModelName);
    String deviceUSER = android.os.Build.USER;
    Log.v("Name USER", "" + deviceUSER);
    String devicePRODUCT = android.os.Build.PRODUCT;
    Log.v("PRODUCT", "" + devicePRODUCT);
    String deviceHARDWARE = android.os.Build.HARDWARE;
    Log.v("HARDWARE", "" + deviceHARDWARE);
    String deviceBRAND = android.os.Build.BRAND;
    Log.v("BRAND", "" + deviceBRAND);
    String myVersion = android.os.Build.VERSION.RELEASE;
    Log.v("VERSION.RELEASE", "" + myVersion);
    int sdkVersion = android.os.Build.VERSION.SDK_INT;
    Log.v("VERSION.SDK_INT", "" + sdkVersion);

插件AndroidManifest.xml：

<uses-permission android:name="android.permission.READ_PHONE_STATE" />

您将通过使用以下代码获得wifi mac地址，无论您在尝试连接到wifi时是否使用了随机地址，也无论wifi是否打开或关闭。

我使用了下面链接中的一个方法，并添加了一个小修改，以获得准确的地址，而不是随机化的地址：

在Android 6.0中获取MAC地址

public static String getMacAddr() {
StringBuilder res1 = new StringBuilder();
try {
List<NetworkInterface> all =     
Collections.list(NetworkInterface.getNetworkInterfaces());
for (NetworkInterface nif : all) {    
if (!nif.getName().equalsIgnoreCase("p2p0")) continue;

        byte[] macBytes = nif.getHardwareAddress();
        if (macBytes == null) {
            continue;
        }

        res1 = new StringBuilder();
        for (byte b : macBytes) {
            res1.append(String.format("%02X:",b));
        }

        if (res1.length() > 0) {
            res1.deleteCharAt(res1.length() - 1);
        }
    }
} catch (Exception ex) {
}
return res1.toString();

}

API级别9（Android 2.3-姜饼）中的Build类中添加了一个Serial字段。文档表示它代表硬件序列号。因此，如果设备上存在，它应该是唯一的。

我不知道API级别>=9的所有设备是否都支持（=不为空）。

正如DaveWebb提到的，Android开发者博客有一篇文章介绍了这一点。他们的首选解决方案是跟踪应用程序安装而不是设备，这对于大多数使用情况都很有效。博客文章将向您展示实现这一功能所需的代码，我建议您查看一下。

然而，如果您需要设备标识符而不是应用程序安装标识符，博客文章将继续讨论解决方案。我与谷歌的某位人士进行了交谈，以获得一些额外的澄清，以防您需要这样做。以下是我发现的有关设备标识符的信息，这些信息在上述博客文章中没有提及：

ANDROID_ID是首选设备标识符。ANDROID_ID在ANDROID<=2.1或>=2.3版本上非常可靠。只有2.2存在帖子中提到的问题。多个制造商的多个设备受到2.2中ANDROID_ID错误的影响。据我所知，所有受影响的设备都具有相同的ANDROID_ID，即9774d56d682e549c。顺便说一下，这也是模拟器报告的相同设备id。谷歌相信，原始设备制造商已经为他们的许多或大部分设备修补了这个问题，但我能够证实，至少在2011年4月初，找到ANDROID_ID损坏的设备仍然很容易。

根据谷歌的建议，我实现了一个类，该类将为每个设备生成一个唯一的UUID，在适当的情况下使用ANDROID_ID作为种子，必要时返回TelephonyManager.getDeviceId（），如果失败，则使用随机生成的唯一UUID，该UUID将在应用程序重新启动（但不是应用程序重新安装）期间保持。

请注意，对于必须在设备ID上回退的设备，唯一ID将在出厂重置期间保持。这是需要注意的。如果您需要确保出厂重置将重置您的唯一ID，您可能需要考虑直接返回到随机UUID而不是设备ID。

同样，此代码用于设备ID，而不是应用安装ID。对于大多数情况，应用安装ID可能是您要查找的。但是，如果您确实需要设备ID，那么下面的代码可能适用于您。

import android.content.Context;
import android.content.SharedPreferences;
import android.provider.Settings.Secure;
import android.telephony.TelephonyManager;

import java.io.UnsupportedEncodingException;
import java.util.UUID;

public class DeviceUuidFactory {

    protected static final String PREFS_FILE = "device_id.xml";
    protected static final String PREFS_DEVICE_ID = "device_id";
    protected volatile static UUID uuid;

    public DeviceUuidFactory(Context context) {
        if (uuid == null) {
            synchronized (DeviceUuidFactory.class) {
                if (uuid == null) {
                    final SharedPreferences prefs = context
                            .getSharedPreferences(PREFS_FILE, 0);
                    final String id = prefs.getString(PREFS_DEVICE_ID, null);
                    if (id != null) {
                        // Use the ids previously computed and stored in the
                        // prefs file
                        uuid = UUID.fromString(id);
                    } else {
                        final String androidId = Secure.getString(
                            context.getContentResolver(), Secure.ANDROID_ID);
                        // Use the Android ID unless it's broken, in which case
                        // fallback on deviceId,
                        // unless it's not available, then fallback on a random
                        // number which we store to a prefs file
                        try {
                            if (!"9774d56d682e549c".equals(androidId)) {
                                uuid = UUID.nameUUIDFromBytes(androidId
                                        .getBytes("utf8"));
                            } else {
                                final String deviceId = (
                                    (TelephonyManager) context
                                    .getSystemService(Context.TELEPHONY_SERVICE))
                                    .getDeviceId();
                                uuid = deviceId != null ? UUID
                                    .nameUUIDFromBytes(deviceId
                                            .getBytes("utf8")) : UUID
                                    .randomUUID();
                            }
                        } catch (UnsupportedEncodingException e) {
                            throw new RuntimeException(e);
                        }
                        // Write the value out to the prefs file
                        prefs.edit()
                                .putString(PREFS_DEVICE_ID, uuid.toString())
                                .commit();
                    }
                }
            }
        }
    }

    /**
     * Returns a unique UUID for the current android device. As with all UUIDs,
     * this unique ID is "very highly likely" to be unique across all Android
     * devices. Much more so than ANDROID_ID is.
     * 
     * The UUID is generated by using ANDROID_ID as the base key if appropriate,
     * falling back on TelephonyManager.getDeviceID() if ANDROID_ID is known to
     * be incorrect, and finally falling back on a random UUID that's persisted
     * to SharedPreferences if getDeviceID() does not return a usable value.
     * 
     * In some rare circumstances, this ID may change. In particular, if the
     * device is factory reset a new device ID may be generated. In addition, if
     * a user upgrades their phone from certain buggy implementations of Android
     * 2.2 to a newer, non-buggy version of Android, the device ID may change.
     * Or, if a user uninstalls your app on a device that has neither a proper
     * Android ID nor a Device ID, this ID may change on reinstallation.
     * 
     * Note that if the code falls back on using TelephonyManager.getDeviceId(),
     * the resulting ID will NOT change after a factory reset. Something to be
     * aware of.
     * 
     * Works around a bug in Android 2.2 for many devices when using ANDROID_ID
     * directly.
     * 
     * @see http://code.google.com/p/android/issues/detail?id=10603
     * 
     * @return a UUID that may be used to uniquely identify your device for most
     *         purposes.
     */
    public UUID getDeviceUuid() {
        return uuid;
    }
}

不建议使用，因为deviceId可以在第三方手中用作跟踪，但这是另一种方式。

@SuppressLint("HardwareIds")
private String getDeviceID() {
    deviceId = Settings.Secure.getString(getApplicationContext().getContentResolver(),
                    Settings.Secure.ANDROID_ID);
    return deviceId;
}

以下是获得AAID的简单答案，测试工作正常2019年6月

 AsyncTask<Void, Void, String> task = new AsyncTask<Void, Void, String>() {
        @Override
        protected String doInBackground(Void... params) {
            String token = null;
            Info adInfo = null;
            try {
                adInfo = AdvertisingIdClient.getAdvertisingIdInfo(getApplicationContext());
            } catch (IOException e) {
                // ...
            } catch ( GooglePlayServicesRepairableException e) {
                // ...
            } catch (GooglePlayServicesNotAvailableException e) {
                // ...
            }
            String android_id = adInfo.getId();
            Log.d("DEVICE_ID",android_id);

            return android_id;
        }

        @Override
        protected void onPostExecute(String token) {
            Log.i(TAG, "DEVICE_ID Access token retrieved:" + token);
        }

    };
    task.execute();

请在此处详细阅读完整答案：