我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。

jQuery是否可以实现这样的功能?

$("#menuscontainer").clickOutsideThisElement(function() {
    // Hide the menus
});

当前回答

如果您正在使用“弹出窗口”等工具,则可以使用“onFocusOut”事件。

window.onload=函数(){document.getElementById(“内部div”).focus();}函数loseFocus(){警报(“在外面单击”);}#集装箱{背景色:浅蓝色;宽度:200px;高度:200px;}#内部div{背景色:浅灰色;宽度:100px;高度:100px;}<div id=“container”><input type=“text”id=“inside div”onfocusout=“loseFocus()”></div>

其他回答

简单插件:

$.fn.clickOff = function(callback, selfDestroy) {
    var clicked = false;
    var parent = this;
    var destroy = selfDestroy || true;

    parent.click(function() {
        clicked = true;
    });

    $(document).click(function(event) {
        if (!clicked && parent.is(':visible')) {
            if(callback) callback.call(parent, event)
        }
        if (destroy) {
            //parent.clickOff = function() {};
            //parent.off("click");
            //$(document).off("click");
            parent.off("clickOff");
        }
        clicked = false;
    });
};

Use:

$("#myDiv").clickOff(function() {
   alert('clickOff');
});

功能:

$(function() {
    $.fn.click_inout = function(clickin_handler, clickout_handler) {
        var item = this;
        var is_me = false;
        item.click(function(event) {
            clickin_handler(event);
            is_me = true;
        });
        $(document).click(function(event) {
            if (is_me) {
                is_me = false;
            } else {
                clickout_handler(event);
            }
        });
        return this;
    }
});

用法:

this.input = $('<input>')
    .click_inout(
        function(event) { me.ShowTree(event); },
        function() { me.Hide(); }
    )
    .appendTo(this.node);

功能非常简单:

ShowTree: function(event) {
    this.data_span.show();
}
Hide: function() {
    this.data_span.hide();
}

如果您正在为IE和FF 3.*编写脚本,并且您只想知道单击是否发生在某个框区域内,您也可以使用以下内容:

this.outsideElementClick=函数(objEvent,objElement){var objCurrentElement=objEvent.target | | objEvent.srcElement;var blnSideX=false;var blnSideY=false;如果(objCurrentElement.getBoundingClientRect().left>=objElement.getBoundingClientRect().left&&objCurrentElement.getBoundingClientRectblnSideX=真;如果(objCurrentElement.getBoundingClientRect().top>=objElement.getBoundingClientRect().ttop&&objCurrentElement.getBoundingClientRectblnSideY=真;如果(blnSideX&&blnSideY)return false;其他的返回true;}

这是我的代码:

// Listen to every click
$('html').click(function(event) {
    if ( $('#mypopupmenu').is(':visible') ) {
        if (event.target.id != 'click_this_to_show_mypopupmenu') {
            $('#mypopupmenu').hide();
        }
    }
});

// Listen to selector's clicks
$('#click_this_to_show_mypopupmenu').click(function() {

  // If the menu is visible, and you clicked the selector again we need to hide
  if ( $('#mypopupmenu').is(':visible') {
      $('#mypopupmenu').hide();
      return true;
  }

  // Else we need to show the popup menu
  $('#mypopupmenu').show();
});
$("body > div:not(#dvid)").click(function (e) {
    //your code
});