我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。

jQuery是否可以实现这样的功能?

$("#menuscontainer").clickOutsideThisElement(function() {
    // Hide the menus
});

当前回答

我在一些jQuery日历插件中找到了这个方法。

function ClickOutsideCheck(e)
{
  var el = e.target;
  var popup = $('.popup:visible')[0];
  if (popup==undefined)
    return true;

  while (true){
    if (el == popup ) {
      return true;
    } else if (el == document) {
      $(".popup").hide();
      return false;
    } else {
      el = $(el).parent()[0];
    }
  }
};

$(document).bind('mousedown.popup', ClickOutsideCheck);

其他回答

要隐藏文件TreeClass(如果在其外部单击),请执行以下操作:

jQuery(document).mouseup(function (e) {
    var container = $(".fileTreeClass");
    if (!container.is(e.target) && // If the target of the click isn't the container...
         container.has(e.target).length === 0) // ... nor a descendant of the container
    {
        container.hide();
    }
});

对于iPad和iPhone等触摸设备,我们可以使用以下代码:

$(document).on('touchstart', function (event) {
    var container = $("YOUR CONTAINER SELECTOR");

    if (!container.is(e.target) &&            // If the target of the click isn't the container...
        container.has(e.target).length === 0) // ... nor a descendant of the container
    {
        container.hide();
    }
});
jQuery().ready(function(){
    $('#nav').click(function (event) {
        $(this).addClass('activ');
        event.stopPropagation();
    });

    $('html').click(function () {
        if( $('#nav').hasClass('activ') ){
            $('#nav').removeClass('activ');
        }
    });
});

解决方案1

不要使用event.stopPropagation(),因为它会产生一些副作用,只需定义一个简单的标志变量并添加一个if条件。我对此进行了测试,工作正常,没有任何stopPropagation的副作用:

var flag = "1";
$('#menucontainer').click(function(event){
    flag = "0"; // flag 0 means click happened in the area where we should not do any action
});

$('html').click(function() {
    if(flag != "0"){
        // Hide the menus if visible
    }
    else {
        flag = "1";
    }
});

解决方案2

只有一个简单的if条件:

$(document).on('click', function(event){
    var container = $("#menucontainer");
    if (!container.is(event.target) &&            // If the target of the click isn't the container...
        container.has(event.target).length === 0) // ... nor a descendant of the container
    {
        // Do whatever you want to do when click is outside the element
    }
});

对于那些希望将一个简短的解决方案集成到JS代码中的人来说——一个没有JQuery的小型库:

用法:

// demo code
var htmlElem = document.getElementById('my-element')
function doSomething(){ console.log('outside click') }

// use the lib
var removeListener = new elemOutsideClickListener(htmlElem, doSomething);

// deregister on your wished event
$scope.$on('$destroy', removeListener);

下面是库:


function elemOutsideClickListener (element, outsideClickFunc, insideClickFunc) {
   function onClickOutside (e) {
      var targetEl = e.target; // clicked element
      do {
         // click inside
         if (targetEl === element) {
            if (insideClickFunc) insideClickFunc();
            return;

         // Go up the DOM
         } else {
            targetEl = targetEl.parentNode;
         }
      } while (targetEl);

      // click outside
      if (!targetEl && outsideClickFunc) outsideClickFunc();
   }

   window.addEventListener('click', onClickOutside);

   return function () {
      window.removeEventListener('click', onClickOutside);
   };
}

我从这里获取代码并将其放在函数中:https://www.w3docs.com/snippets/javascript/how-to-detect-a-click-outside-an-element.html