我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。
jQuery是否可以实现这样的功能?
$("#menuscontainer").clickOutsideThisElement(function() {
// Hide the menus
});
我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。
jQuery是否可以实现这样的功能?
$("#menuscontainer").clickOutsideThisElement(function() {
// Hide the menus
});
当前回答
这是一个经典的例子,对HTML进行调整将是更好的解决方案。为什么不在不包含菜单项的元素上设置单击?那么您不需要添加传播。
$('.header, .footer, .main-content').click(function() {
//Hide the menus if visible
});
其他回答
标记为接受答案的答案没有考虑到元素上可以有覆盖,如对话框、弹出窗口、日期选择器等。单击这些按钮不应隐藏元素。
我制作了自己的版本,确实考虑到了这一点。它是作为KnockoutJS绑定创建的,但它可以很容易地仅转换为jQuery。
它通过第一次查询所有具有z索引或绝对位置的可见元素来工作。然后,如果在外部单击,它会根据我想要隐藏的元素来测试这些元素。如果是命中,我会计算一个新的边界矩形,该矩形考虑到覆盖边界。
ko.bindingHandlers.clickedIn = (function () {
function getBounds(element) {
var pos = element.offset();
return {
x: pos.left,
x2: pos.left + element.outerWidth(),
y: pos.top,
y2: pos.top + element.outerHeight()
};
}
function hitTest(o, l) {
function getOffset(o) {
for (var r = { l: o.offsetLeft, t: o.offsetTop, r: o.offsetWidth, b: o.offsetHeight };
o = o.offsetParent; r.l += o.offsetLeft, r.t += o.offsetTop);
return r.r += r.l, r.b += r.t, r;
}
for (var b, s, r = [], a = getOffset(o), j = isNaN(l.length), i = (j ? l = [l] : l).length; i;
b = getOffset(l[--i]), (a.l == b.l || (a.l > b.l ? a.l <= b.r : b.l <= a.r))
&& (a.t == b.t || (a.t > b.t ? a.t <= b.b : b.t <= a.b)) && (r[r.length] = l[i]));
return j ? !!r.length : r;
}
return {
init: function (element, valueAccessor) {
var target = valueAccessor();
$(document).click(function (e) {
if (element._clickedInElementShowing === false && target()) {
var $element = $(element);
var bounds = getBounds($element);
var possibleOverlays = $("[style*=z-index],[style*=absolute]").not(":hidden");
$.each(possibleOverlays, function () {
if (hitTest(element, this)) {
var b = getBounds($(this));
bounds.x = Math.min(bounds.x, b.x);
bounds.x2 = Math.max(bounds.x2, b.x2);
bounds.y = Math.min(bounds.y, b.y);
bounds.y2 = Math.max(bounds.y2, b.y2);
}
});
if (e.clientX < bounds.x || e.clientX > bounds.x2 ||
e.clientY < bounds.y || e.clientY > bounds.y2) {
target(false);
}
}
element._clickedInElementShowing = false;
});
$(element).click(function (e) {
e.stopPropagation();
});
},
update: function (element, valueAccessor) {
var showing = ko.utils.unwrapObservable(valueAccessor());
if (showing) {
element._clickedInElementShowing = true;
}
}
};
})();
试试这个:
$('html').click(function(e) {
if($(e.target).parents('#menuscontainer').length == 0) {
$('#menuscontainer').hide();
}
});
https://jsfiddle.net/4cj4jxy0/
但请注意,如果单击事件无法到达html标记,则这将无法工作。(可能其他元素已停止传播())。
我只是想让@Pistos的回答更加明显,因为它隐藏在评论中。
这个解决方案非常适合我
var elementToToggle = $('.some-element');
$(document).click( function(event) {
if( $(event.target).closest(elementToToggle).length === 0 ) {
elementToToggle.hide();
}
});
在CoffeeScript中:
elementToToggle = $('.some-element')
$(document).click (event) ->
if $(event.target).closest(elementToToggle).length == 0
elementToToggle.hide()
外部点击插件!
用法:
$('.target-element').outsideClick(function(event){
//code that fires when user clicks outside the element
//event = the click event
//$(this) = the '.target-element' that is firing this function
}, '.excluded-element')
它的代码:
(function($) {
//when the user hits the escape key, it will trigger all outsideClick functions
$(document).on("keyup", function (e) {
if (e.which == 27) $('body').click(); //escape key
});
//The actual plugin
$.fn.outsideClick = function(callback, exclusions) {
var subject = this;
//test if exclusions have been set
var hasExclusions = typeof exclusions !== 'undefined';
//switches click event with touch event if on a touch device
var ClickOrTouchEvent = "ontouchend" in document ? "touchend" : "click";
$('body').on(ClickOrTouchEvent, function(event) {
//click target does not contain subject as a parent
var clickedOutside = !$(event.target).closest(subject).length;
//click target was on one of the excluded elements
var clickedExclusion = $(event.target).closest(exclusions).length;
var testSuccessful;
if (hasExclusions) {
testSuccessful = clickedOutside && !clickedExclusion;
} else {
testSuccessful = clickedOutside;
}
if(testSuccessful) {
callback.call(subject, event);
}
});
return this;
};
}(jQuery));
根据此答案改编https://stackoverflow.com/a/3028037/1611058
$(document).on('click.menu.hide', function(e){
if ( !$(e.target).closest('#my_menu').length ) {
$('#my_menu').find('ul').toggleClass('active', false);
}
});
$(document).on('click.menu.show', '#my_menu li', function(e){
$(this).find('ul').toggleClass('active');
});
div {
float: left;
}
ul {
padding: 0;
position: relative;
}
ul li {
padding: 5px 25px 5px 10px;
border: 1px solid silver;
cursor: pointer;
list-style: none;
margin-top: -1px;
white-space: nowrap;
}
ul li ul:before {
margin-right: -20px;
position: absolute;
top: -17px;
right: 0;
content: "\25BC";
}
ul li ul li {
visibility: hidden;
height: 0;
padding-top: 0;
padding-bottom: 0;
border-width: 0 0 1px 0;
}
ul li ul li:last-child {
border: none;
}
ul li ul.active:before {
content: "\25B2";
}
ul li ul.active li {
display: list-item;
visibility: visible;
height: inherit;
padding: 5px 25px 5px 10px;
}
<script src="https://code.jquery.com/jquery-2.1.4.js"></script>
<div>
<ul id="my_menu">
<li>Menu 1
<ul>
<li>subMenu 1</li>
<li>subMenu 2</li>
<li>subMenu 3</li>
<li>subMenu 4</li>
</ul>
</li>
<li>Menu 2
<ul>
<li>subMenu 1</li>
<li>subMenu 2</li>
<li>subMenu 3</li>
<li>subMenu 4</li>
</ul>
</li>
<li>Menu 3</li>
<li>Menu 4</li>
<li>Menu 5</li>
<li>Menu 6</li>
</ul>
</div>
这里是jsbin版本http://jsbin.com/xopacadeni/edit?html,css,js,输出