function getFormData($form){
    var unindexed_array = $form.serializeArray();
    var indexed_array = {};

    $.map(unindexed_array, function(n, i){
        if(indexed_array[n['name']] == undefined){
            indexed_array[n['name']] = [n['value']];
        }else{
            indexed_array[n['name']].push(n['value']);
        }
    });

    return indexed_array;
}

显示表单输入元素字段和输入文件提交您的表单没有页面刷新和抓取所有值与文件包括在这里

<form id="imageUploadForm" action="" method="post" enctype="multipart/form-data"> <input type="text" class="form-control" id="fname" name='fname' placeholder="First Name" > <input type="text" class="form-control" name='lname' id="lname" placeholder="Last Name"> <input type="number" name='phoneno' class="form-control" id="phoneno" placeholder="Phone Number"> <textarea class="form-control" name='address' id="address" rows="5" cols="5" placeholder="Your Address"></textarea> <input type="file" name="file" id="file" > <input type="submit" id="sub" value="Registration"> </form> on Submit button page will send ajax request to your php file. $('#imageUploadForm').on('submit',(function(e) { fname = $('#fname').val(); lname = $('#lname').val(); address = $('#address').val(); phoneno = $('#phoneno').val(); file = $('#file').val(); e.preventDefault(); var formData = new FormData(this); formData.append('file', $('#file')[0]); formData.append('fname',$('#fname').val()); formData.append('lname',$('#lname').val()); formData.append('phoneno',$('#phoneno').val()); formData.append('address',$('#address').val()); $.ajax({ type:'POST', url: "test.php", //url: '<?php echo base_url().'edit_profile/edit_profile2';?>', data:formData, cache:false, contentType: false, processData: false, success:function(data) { alert('Data with file are submitted !'); } }); }))

$("#form input, #form select, #form textarea").each(function() {
 data[theFieldName] = theFieldValue;
});

除此之外，你可能想看看serialize();

我已经包括答案，也给回所需的对象。

function getFormData(form) {
var rawJson = form.serializeArray();
var model = {};

$.map(rawJson, function (n, i) {
    model[n['name']] = n['value'];
});

return model;
}

现在是2019年，有一个更好的方法:

const form = document.querySelector('form');
const data = new URLSearchParams(new FormData(form).entries());

或者如果你想要一个普通的对象

const form = document.querySelector('form');
const data = Object.fromEntries(new FormData(form).entries());

尽管请注意，这将不适用于重复的键，如您从多选和重复的复选框具有相同的名称。

$(form).serializeArray().reduce(function (obj, item) {
      if (obj[item.name]) {
           if ($.isArray(obj[item.name])) {
               obj[item.name].push(item.value);
           } else {
                var previousValue = obj[item.name];
                obj[item.name] = [previousValue, item.value];
           }
      } else {
           obj[item.name] = item.value;
      }

     return obj;
}, {});

它将修复问题:无法与多选择工作。