删除所有重复项，但删除第一个重复项(具有最小ID)

应该同样适用于其他SQL服务器，如Postgres:

DELETE FROM table
WHERE id NOT IN (
   select min(id) from table
   group by col1, col2, col3, col4, col5, col6, col7
)

请参见下面的删除方式。

Declare @table table
(col1 varchar(10),col2 int,col3 int, col4 int, col5 int, col6 int, col7 int)
Insert into @table values 
('john',1,1,1,1,1,1),
('john',1,1,1,1,1,1),
('sally',2,2,2,2,2,2),
('sally',2,2,2,2,2,2)

创建一个名为@table的样例表，并用给定的数据加载它。

Delete  aliasName from (
Select  *,
        ROW_NUMBER() over (Partition by col1,col2,col3,col4,col5,col6,col7 order by col1) as rowNumber
From    @table) aliasName 
Where   rowNumber > 1

Select * from @table

注意:如果您按部分给出分区中的所有列，那么按顺序没有多大意义。

我知道，这个问题是三年前问的，我的答案是蒂姆发布的另一个版本，但发布只是为了对任何人有帮助。

另一种在不丢失信息的情况下删除重复行的方法如下:

delete from dublicated_table t1 (nolock)
join (
    select t2.dublicated_field
    , min(len(t2.field_kept)) as min_field_kept
    from dublicated_table t2 (nolock)
    group by t2.dublicated_field having COUNT(*)>1
) t3 
on t1.dublicated_field=t3.dublicated_field 
    and len(t1.field_kept)=t3.min_field_kept

-- this query will keep only one instance of a duplicate record.
;WITH cte
     AS (SELECT ROW_NUMBER() OVER (PARTITION BY col1, col2, col3-- based on what? --can be multiple columns
                                       ORDER BY ( SELECT 0)) RN
         FROM   Mytable)



delete  FROM cte
WHERE  RN > 1

在sql server中可以通过多种方式来实现 最简单的方法是: 将重复行表中的不同行插入到新的临时表中。然后从重复的行表中删除所有数据，然后从没有重复的临时表中插入所有数据，如下所示。

select distinct * into #tmp From table
   delete from table
   insert into table
   select * from #tmp drop table #tmp

   select * from table

使用公共表表达式(CTE)删除重复行

With CTE_Duplicates as 
(select id,name , row_number() 
over(partition by id,name order by id,name ) rownumber  from table  ) 
delete from CTE_Duplicates where rownumber!=1

不使用CTE和ROW_NUMBER()，您可以通过使用group by和MAX函数删除记录，这里是一个例子

DELETE
FROM MyDuplicateTable
WHERE ID NOT IN
(
SELECT MAX(ID)
FROM MyDuplicateTable
GROUP BY DuplicateColumn1, DuplicateColumn2, DuplicateColumn3)