我正在寻找一种有效的方法，从javascript数组中删除所有元素，如果它们存在于另一个数组中。
// If I have this array:
var myArray = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
// and this one:
var toRemove = ['b', 'c', 'g'];
我想对myArray进行操作，使其处于这种状态:['a'， 'd'， 'e'， 'f']
与jQuery，我使用grep()和inArray()，这工作得很好:
myArray = $.grep(myArray, function(value) {
return $.inArray(value, toRemove) < 0;
});
有没有一个纯javascript的方法来做到这一点没有循环和剪接?
当前回答
//Using the new ES6 Syntax console.log(["a", "b", "c", "d", "e", "f", "g"].filter(el => !["b", "c", "g"].includes(el))); // OR // Main array let myArray = ["a", "b", "c", "d", "e", "f", "g"]; // Array to remove const toRemove = ["b", "c", "g"]; const diff = () => (myArray = myArray.filter((el) => !toRemove.includes(el))); console.log(diff()); // [ 'a', 'd', 'e', 'f' ] // OR const diff2 = () => { return myArray = myArray.filter((el) => !toRemove.includes(el)); }; console.log(diff2()); // [ 'a', 'd', 'e', 'f' ]
其他回答
你可以使用_。by和lodash的区别
const myArray = [
{name: 'deepak', place: 'bangalore'},
{name: 'chirag', place: 'bangalore'},
{name: 'alok', place: 'berhampur'},
{name: 'chandan', place: 'mumbai'}
];
const toRemove = [
{name: 'deepak', place: 'bangalore'},
{name: 'alok', place: 'berhampur'}
];
const sorted = _.differenceBy(myArray, toRemove, 'name');
示例代码:CodePen
如果你不能使用新的ES5的东西这样的过滤器，我认为你被困在两个循环:
for( var i =myArray.length - 1; i>=0; i--){
for( var j=0; j<toRemove.length; j++){
if(myArray[i] === toRemove[j]){
myArray.splice(i, 1);
}
}
}
ECMAScript 6集合可以更快地计算一个数组中不在另一个数组中的元素:
const myArray = [a, b, c, d, e, f, g的); const toRemove = new Set(['b'， 'c'， 'g']); const difference = myArray。toRemove.has(x)); console.log(差异);// ["a"， "d"， "e"， "f"]
因为现在V8引擎浏览器使用的查找复杂度是O(1)，所以整个算法的时间复杂度是O(n)。
//Using the new ES6 Syntax console.log(["a", "b", "c", "d", "e", "f", "g"].filter(el => !["b", "c", "g"].includes(el))); // OR // Main array let myArray = ["a", "b", "c", "d", "e", "f", "g"]; // Array to remove const toRemove = ["b", "c", "g"]; const diff = () => (myArray = myArray.filter((el) => !toRemove.includes(el))); console.log(diff()); // [ 'a', 'd', 'e', 'f' ] // OR const diff2 = () => { return myArray = myArray.filter((el) => !toRemove.includes(el)); }; console.log(diff2()); // [ 'a', 'd', 'e', 'f' ]
最简单的方法如何:
var myArray = [a, b, c, d, e, f, g的); var toRemove = ['b'， 'c'， 'g']; var myArray = myArray.filter((item) => ! console.log (myArray)
